Recent content by xxpbdudexx

v = -u where u = 69.3 m/s. So: 69.3 = -69.3 +at I don't know the resultant acceleration so I assume I am doing something wrong in coming up with this equation from what you have said.

Usually these problems are really simple for me, but this one is making me lose my mind: "An archer wishes to shoot an arrow at a target at eye level a distance of 49.0 m away. If the initial speed imparted to the arrow is 69.3 m/s, what angle should the arrow make with the horizontal as it is...

Alright, I did this and found out ma = mgμ, and then subsequently solved it. Thanks.

Here is the problem: "A small package rests on the horizontal dashboard of a car. If μs = 0.333, what is the minimum acceleration of the car that will cause the package to slip off, assuming that the car is on a level road?" I really have no clue. Any equations I feel are relevant (μ...

I see. So the different factorings are merely due to a factored -1. That makes sense. So then, with the second problem, the equation must be equal to zero in order to the zero product property? Okay, thanks, that helps a lot.

As it turns out, this first part was an extremely pervasive user error that I have not seen for days. Still, though, it is interesting that equations can be factored in many different ways, so I will post that here instead: 3x^3 = -5x^2 +2x -3x^3 -5x^2 + 2x = 0 Factored: x(-3x+1)(x+2) and...

I have always thought centrifugal force existed. My physics teacher last year told me it doesn't. I did some research on centrifugal and centripetal force and am still convinced centrifugal force exists as the equal and opposite force to centripetal force. What do you guys think?

Third one is it. Thanks.

1. Um, at the highest point of the arc, the v=0, and there are 2 times for 1 height. 2. I don't have one. 3. My teacher gave us 3 formulas and I didn't copy them down. I need the other formula I can't remember. 4. I'm not sure. Sorry I have no more information.

What do you mean both are wrong? And also what do you mean by understanding the derivation? Will that help me in some way? I just need to know this missing formula that I didn't copy down.

I looked at the sticky, but could not find what I needed. I got a trio of new formulas today, but I never copied them down. I remembered the first two because I used them today, but I cannot recall the other one. The subject is Projectiles Launched at an Angle and the 2 I have are: R=...

Yeah, I got it. :) Thanks again.

Oh my God! I did it using the Pythagorean theorem! Thank you so much for your help!

OK, so Vf of y is -6.93 m/s. You said I could use that to find Vf, thus Vi. How would I go about doing that?

My main, question, I suppose, is, is the question asking me to solve (V0)y or (V0)x? I'm assuming y. But, I also have already assumed that the V initial for y is zero, so what exactly am I solving for?!