Recent content by yayscience
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Graduate How Do We Derive the Transmission Line Equations Using Differential Methods?
Eqn. (2.1) \frac{\partial v}{\partial z} = -L \frac{\partial i}{\partial t} Eqn. (2.2) \frac{\partial i}{\partial z} = -C \frac{\partial v}{\partial t} Eqn. (2.5) v(z,t)=V^+f(t-\frac{z}{v_p})+V^-f(t+\frac{z}{v_p}) From the book I'm reading: "By substituting Equation (2.5) into Equations...- yayscience
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- Derivation Line Transmission Transmission line
- Replies: 1
- Forum: Electromagnetism
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Undergrad Expansion of 1/(1+quantity) in Coulomb's Law
I'm watching some lectures on electromagnetism from NPTEL on Youtube. Lecture 3 on Coulomb's Law, at 29minutes: http://www.youtube.com/watch?v=0A45kt2U3U8&feature=player_profilepage#t=1740s The professor expands this: \frac{1}{1+\frac{2dsin(\theta)}{r_1}} into...- yayscience
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- Expansion
- Replies: 4
- Forum: Calculus
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Using cross product to find angle between two vectors
Oh wow; I didn't even consider that the answer wasn't unique. Thanks!- yayscience
- Post #6
- Forum: Calculus and Beyond Homework Help
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Using cross product to find angle between two vectors
I can plot them, and I can see the angle, but I'm interested in calculating the angle. When I use the dot product I get the correct result, but I cannot see where my mistake is while using the cross product.- yayscience
- Post #4
- Forum: Calculus and Beyond Homework Help
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Using cross product to find angle between two vectors
Homework Statement Find the angle between \begin{align*} \vec{A} = 10\hat{y} + 2\hat{z} \\ and \\ \vec{B} = -4\hat{y}+0.5\hat{z} \end{align*} using the cross product. The answer is given to be 161.5 degrees. Homework Equations \left| \vec{A} \times \vec{B} \right| = \left|...- yayscience
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- Angle Cross Cross product Product Vectors
- Replies: 5
- Forum: Calculus and Beyond Homework Help