Recent content by yellowfish

Okay would it then be m1(√ [(vcos30)^2+(vsin30)^2] ) = m1ucos30 + m2scos30 m1(√ [(vcos30)^2+(vsin30)^2] ) = m1usin30 + m2ssin30

Since its an elastic collision and the masses are constant then the initial velocity v = final velocity of particle 1(call it u) + velocity of particle 2(call it s). Resolving those into the x and y components would therefore give for particle 1 u(x component)cos(30) and u(y component)sin(30)...

Thanks for your response, so would it be, Initial momentum = final momentum m1v = (m1 + m2)(v(y component)/sin(30)) and m1v = (m1 + m2)(v(x component)/cos(30)) ?

Homework Statement A particle (of mass m velocity v) makes a perfect elastic collision with a stationary particle. After the collision both particles travel 30 degrees from original path. Use conservation of momentum/energy to obtain 3 equations relating the masses/velocities. Homework...