Recent content by yeuVi

Oh, I was following his hint...

Oh, it's not the area is 0, but the limit of the integral is 0...

The 1st one, I integrated it by substitution u= x^2+2 so the integration is 1/4 * 8* (u^(1/8)) It's converge to 0, so the area 's finite...

Thanx a lot. I tried ur hints and got some results. Can u guys check if they correct? The 1st one, I got the area is finite... The 2nd one, the sequence is convergence, since \ \lim{0} = \lim{ \frac{2}{n^3}} =0 so \ \lim{a_n}=0 therefore the sequence is converge to 0...

But the first one, after I get the integrate, what should I do next? I mean, it's is finite if the integrate limit is converge? The secon one, I do not really understand the hint... can u explain a little more detail? I guess you want me to apply the comparion limit test for a sequence? I...

There are two problems I got stuck... 1. Is the area in the first quadrant bounded between the x-axis and the curve \ y= \frac{x} {2*(x^2+2)^{7/8}} finite? This one, I used the Area formula... but then I cannot integrate it... and then how to determine if it's finite or not? 2...

Thank you very much... now I got the problem...^_^

Im sorry... You lost me... I guess what u try to say is that I substituted y with (y+3) in the integral formula?

Well, I just need to know how to adjust that integral with the vertical line at x=3... the formula is easy, but the interval of integral should be ...?

If around the y-axis, then the integral should be \int 2\pi*y^{1/3}* \sqrt{1+ {1/9}*y^{-4/3}}*dy right? From then, what change should I make to adjust with that x=3 vertical line?

Surface area help please... How do you find a surface area of a function around a vertical line? For example: surface of \ y=x^3 between \ 0<= x <= 3, rotating around \ x=4? I tried the formula for finding surface area, but I confuse with that vertical line x=4... what should I do?

Help with paremetic I need help with these... I can't read them... \color{blue} a): \ \ \ \ \mathsf{ Eq \ for \ "x" \ indicates \ t_{1} = -t_{2} \ \ \ \ \ \ \ Eq \ for \ "y" \ uses \ next \ hint } \color{blue} b): \ \ \ \ \frac { t_{1}^{3} \ - \ t_{2}^{3} } { t_{1} \ - \ t_{2} } \ = \...