Ok i did some math, but am no close to solution. I am able to reconcile Special Relativity energies, and I am also able to relate it to the dB wave's energy. But not sure if i still understand it. Here is what I did.
Take an electron traveling at 2.5 x 108 m/s (relativistic effects will be...
Do you mean to say if i plugged in the relativistic formula for Mass, hf will be equal to the rest energy (m0c2) plus kinetic energy of particle mv2/2 (where m0 is rest mass and m is the relativistic mass)?
I also understand dB waves have phase and group velocities (and phase velocity is...
Using this relation, energy of wave = hf = mv2.
What does mv2 mean? We know mv2/2 is K.E. of the particle. Why is the energy of dB wave twice the K.E.?
So if the wavelength of an electron is 1.2 x 10e(-10), what is its frequency?
Knowing λ, I can calculate the electron's velocity as v = h/mλ. I get v = 6.07 x 10e(6).
And now f = v/λ, which comes to 5.05 x 10e(16).
Is this right?
I am confused about de Broglie waves.
we know λ = h/mv
What is the frequency of the dB wave?
Generally, speed of any wave v = fλ.
Is the frequency of dB wave f = v / λ, where v is the speed of the particle (ignoring Special relativity effects)?