Recent content by yonathan

so what is d/dh of e^-h/c

it represents the differentiation of P which is P.

sorry i still don't follow, can u explain it to me in another way or something? i don't know wat to do with the last answer u gave me. do i substitute my numbers on ur answer and wat is e^f(h), how am i suppose to solve it?

what is 'f' in ur chain rule cause according to it the derivative is f(h)is -h/c??

so the first derivative of Po e^-h/c is dp/dh=Poe^f(h), where f(h)is -h/c, and after this, all i have to do is substitute the numbers given, yeh? and i am sure about the derivative u asked me.

the derivative of e^f(x) is (f)e^f(x) but what if it was e^(F/x) that's what i want to find out??

what jeffreydk wrote is what i want to figure out exactly, if you can help in that it would be very helpful.

that was wat i was tyin to find,but i am not sure. i came with the answers i showed u where i added 'or' (the one u put at the end of ur message before this message) and i don't think it is wright, do u think it was right?

the reason put or (where u quoted it at the end of ur message) was to ask u which of the answers i came up with was the correct one.

the pressure P of the atmosphere at height 'h' above ground level is given by P=Po e^-h/c where Po is the pressure at ground level and c is the constant.determine the rate of change of pressure with height when Po=1.013*10^5 pascals C=6.05*10^4 at 1450 meters. i used the for differentiation to...

can u pls help me with this quaestion? p=Po e^-h/c