Recent content by yosup231

.23 m/s (2pi/T)A (spi/.75)(.142sin11)= .23m/s

is teh answer by any chance .16 or .23

difference is .142m - .03m i don't see how it helps

c'mon 11 views no help I am sure someone out there knows it

Please Help! ok could someone plesae help me with this question I had to draw a pendulum and the questions asks what is the length of the pendulum if the period is .75 s so i got .142 m then it asks what is the speed of the pendulum at the bottom of its swing if the angle that makes its...

c'mon i have 60 more minutes to get this done i think i figured out some stuff but I am not sure WILL SOMEONE PLEASE HELP i did 60kg x 10m/s^2 x .12 x cos 12= 70.4 200N-70.4N=129.6 N 129.6N x 100m=12960 J then I am not sure what else to do PLEASE PLEASE HELP ME

Please this is urgent someone answer

well i did: 60kg x sin 12= 12.47kg 200N x .12 x cos 12=23.47N 200N-23.47N= 176.53N 176.53N/12.47kg= 14.52 m/s^2 Vf^2=0+2(14.2m/s^2)(100m) Vf=53.3 m/s Now I know this is wrong could you please explain to me where i went wrong

other question Using her snowmobile, Midge pulls a 60.0 kh skier up a ski slope inclined at an angle of 12.0 degrees to the horizontal. The snowmobile exerts a force of 200.0 N parallel to the hill. If the coeficient of friction between the skis and hte snow is 0.120, how fast is the skier...

ok... but how about the other question that's the one that I am having a lot of trouble with

C'mon its been two days; isn't there someone who could help me with these questions? Your help would be greatly appreciated.

come on please I am sure someone here knows how to do these problems :confused:

im kind of new at this... why does it say my post has been moved?? CAN SOMEONE PLEASE HELP ME OUT WITH THIS QUESTION?! EDIT: n/m i see i should have posted this in the homework question section

okay so i guess i would do this: (4727 kg)(10m/s^2)(21.9 m)=1035213J 1611907J-1035213J= 576694J (is that right) can anyone help with the second question

Energy questions?? ok i have two questions which i am completely stumped on and i need some help... At riverside park in Agawam, Massachusetts, a ride called the cyclone is a giant roller coaster that ascends a 34.1 m hill and then drops 21.9 m before ascending the next hill. THe train of...