Recent content by Yousra

In this situation we have both linear kinetic energy and the rolling kinetic energy, so: KR= 0,5.I.ω2 =0,5.2/5.m.r2. (v2/r2) =1/5.m.v2 and Klin=0,5.m.v2 we also have the potential energy: E=m.g.h with h= R-r (we don't have to forget to subtract the radius of the ball to the...