Recent content by yyuy1

well, this is only a small part of the original problem. the Helmholtz equation is actually a diffusion equation in steady state (in frequency domain), so all of the parameters Ez, I and so on are actually phasors (I'm not sure this is the right way to describe them in english..). Anyway, they...

well, I'm totally clueless regarding that integral equation I've tried use Mathematica, but that didn't really work out what do you think I should do next?

thank you so much for the help I can't tell you how much I appreciate it

man... that's amazing.. thanks allot. nevertheless, this still doesn't resolve the logarithm column issue..

for some reason I'm unable to see your reply here although I've received it in my mailbox..

well, ky is obviously positive in order for the function to decay as it goes to y -> -inf

ky is complex, so that the real part of ky^2 cancels out with kx^2 and then the imaginary part is j\omega\sigma *(by the way, thanks allot for all this help)

aha. does this mean that Kx must be real or that sin(Kx*x) is not the right solution?

well, then Kx must be complex. the real part of Kx^2 will cancel out with the Ky^2 and the imaginary part will be j\omega\sigma. is this correct?

well, I do know that {K_x}^2-{K_y}^2=j\omega\sigma

the logarithmic boundary condition is odd, which led me to believe that the solution X(x) is expandable to a sine column. the boundary condition E_z(y\rightarrow-\infty)=0 together with the logarithmic boundary condition on X mean that Y should be a positive constant in y=0 and decay to 0 as...

yes, I have. Actually, It's not really a total guess, it is pretty intuitive ... anyhow, I assumed that the problem was separable Ez=X(x)Y(y), and since the boundary condition on X is odd it should be expandable to a sine column. The Y part is probably a decaying exponent due to it's boundary...

well, the proposed solution was sort of a guess, but take in mind that the sine part was supposed to be a sum of a sine series and therefore I would hope to make sure it does converge properly.

okay, I think I understand your point (what I meant was x\rightarrow\pm\infty) how do you suggest I approach this problem? I am having difficulty with the fact that the boundary condition is not periodic. (hence it is impossible to find a Fourier series expansion for it) thanks again

thanks for the quick response gabbagabbahey unfortunately I currently have no Latex capabilities. hopefully I will manage to learn it in the future. The solution will approach 0 in y\rightarrow\pm\infty due to behavior of the boundary condition on Ez(y=0). my problem is in finding an...