Recent content by Zachary

that's true. it is useful in the data analysis in the experiment..:smile:

sorry.. I meant x^2=-(-1)*x^2=-(i^2)*(x^2)=-i*(i*x^2) so that i can use e^ix=cosx+isinx. But D H has provided the answer, that is quite nice.

You are right! It is integrated from negative infinity to positive infinity. I get one method to do that, but have another problem.. e^(x^2)=e^(-i)*e^(ix^2)=e^(-i)*(cos(x^2)+isin(x^2)) I try to integrate sin(x^2) or cos(x^2) instead, however, i haven't get it yet:confused: