Recent content by Zack88

  1. Z

    Evaluating the integral, correct?

    k cya thanks again
  2. Z

    Evaluating the integral, correct?

    lol so in other words was the square already completed?
  3. Z

    Evaluating the integral, correct?

    wouldnt the 9 - 9 cancel out? so ur still left with the original problem.
  4. Z

    Evaluating the integral, correct?

    ok came across a bump. [integral] dx/ x^2 - 6x + 13 so i have to complete the square, so x^2 - 6x + 13 = 0 x^2 - 6x = -13 wait before i continue I always thought anything that was negative and squared it become positive but now my calculator is telling me differently. the...
  5. Z

    Evaluating the integral, correct?

    oh ok and i just made up the example so if i have a number higher than 1 I need to divide that number out so ex. 5x^2 + 6x + 5 and then id divide the whole thing by 5.
  6. Z

    Evaluating the integral, correct?

    I don't know what that means, since i work with the square root do I not pay attention to it until finally getting the final answer. ex. x^3 + 6x^2 - 4 then x^3 + 6x^2 = 4 x^3 + 6x^2 + 9 = 4 + 9 and so on
  7. Z

    Evaluating the integral, correct?

    more like 1 / 9x^2 + 6x -8
  8. Z

    Evaluating the integral, correct?

    hey when completing the square when a square roots is involved, do you square both sides?
  9. Z

    Evaluating the integral, correct?

    sorry if i was irritating you it has been a year since I've done any math and I am jumping into calc 2, but i finally got it and I have done most of the rest, just three left which I am working on now, so thank you for all your help and putting up with me :)
  10. Z

    Evaluating the integral, correct?

    [integral] x/2 (1 + cos2x) [chain rule] [integral] x/2 (-2sin2x) + (1 + cos2x)(1/2) = x^2 /4 (cos2x) + (((sin(2x) / 2) + x)) (x/2) = (x^2 cos 2x) / 4 + x(sin2x / 2 + x/2)
  11. Z

    Evaluating the integral, correct?

    ok [integral] x cox^2 x dx turns into [integral] x/2(1 + cos2x) dx
  12. Z

    Evaluating the integral, correct?

    [integral] x cox^2 x dx u= x du = dx dv= cos^2 v= (sin(2x)) / 4 + x/2 x (sin(2x)) / 4 + x/2 - [integral] (sin(2x)) / 4 + x/2 du x (sin(2x)) / 4 + x/2 + cos(2x) / 8 + x^2 / 4 + c i know the answer is x (sin(2x)) / 4 + cos(2x) / 8 + x^2 / 4 + c but I got an extra x/2
  13. Z

    Evaluating the integral, correct?

    thank you must have wrote it down wrong on paper, but does that matter since i didnt use that identity?
  14. Z

    Evaluating the integral, correct?

    i know the answer is close to that except for the extra x/2
  15. Z

    Evaluating the integral, correct?

    [integral] x cox^2 x dx u= x du = dx dv= cos^2 v= (sin(2x)) / 4 + x/2 x (sin(2x)) / 4 + x/2 - [integral] (sin(2x)) / 4 + x/2 du x (sin(2x)) / 4 + x/2 + cos(2x) / 8 + x^2 / 4 + c
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