Thank you for the LaTex help.
When you say "o R.." what does the 'o' stand for? Are you saying 'of' ? R of exp? I just want to make sure I'm on the same page as you.
Thanks again.
The test question was the original question.
Find the inverse of: y = \frac{1-e^-x}{e^x+1}
(again, that should be negative x exponent in the numerator)
No, this was a calc 1 exam that covered some review of old stuff as well as lmits and beginning derivatives. This was the problem.
If this was a positve x in the exponent it would be easy to solve.
Well you see, this was a test question tonight on a calculus test I had and I came home racking my brain trying to figure out where I went wrong.
AKG, are you saying that this does not have an inverse unless its in the domain you specified above?
Ok, rookie question.. but I have no one to verify it other than you folks.
Please help me out if you can.
Problem: Find the inverse of y = \frac{1-e^-x}{e^x+1}
The question is... can you do this:
y = \frac{1-e^-x}{e^x+1} = y = \frac{1}{e^x + 1 - e^x} = \frac{1}{1} = 1
I thought this...
Ok, thanks for the help thus far. I was able to remember (through the help of another math friend) that if all the coefficients of the polynomial add up to zero, it is divisble by x-1 and x-1 is one of the factors. Therefore I had to take x-1 and divide it into x^3 - 3x^2 -6x+8 and I was given...
I'm in calculus, but we're having this test on some curve sketing soon and I'm doing some practice problems that the teacher gave us. We're not allowed to use a calculator in this calculus class (except for very rare instances) so we have to know how to sketch graphs with no problem!
I'm...