Recent content by zpmodel
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Solving Parachutist Problem: Force Exerted by Parachute
Problem solved; Sweet! What an awesome forums. I just started in the science field so I'll be probably be around for the next few years. Thanks a lot for all your help!- zpmodel
- Post #9
- Forum: Introductory Physics Homework Help
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Solving Parachutist Problem: Force Exerted by Parachute
I realized I had V2 and V1 mixed around, it should have been: V22 = V12 + 2(a)(d) 102 = 502 + 2(a)(40) a = -30m/s/s Which makes sense now because he is accelerating downwards (negative). F = ma F = (100)(-30) F = -3000N upwards Hmm, so the net force is -3000N. So, Fnet = F1 + F2...- zpmodel
- Post #7
- Forum: Introductory Physics Homework Help
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Solving Parachutist Problem: Force Exerted by Parachute
Ohhhh yeaah: V2 = V1 + (a)(t) 10 = 50 + (a)(t) Correct? But why isn't the time 4 seconds? I thought that the velocity was the distance divided by time; so: 10m/sec = 40m / seconds seconds = 4 Nevertheless, there's this kinematic equation as well: V22 = V12 + 2(a)(d) 502 =...- zpmodel
- Post #5
- Forum: Introductory Physics Homework Help
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Solving Parachutist Problem: Force Exerted by Parachute
Alright. Forces on parachutist, that would be 100kg times the force of gravity, so 980N down? But I think that's his wieght, not his force... His acceleration is his force divided by his mass, but I am only given the velocity. But I could find the acceleration by finding the slope of the...- zpmodel
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Molarity of a Solution: Aluminum Salt and Unreacted Sulphuric Acid
I have problem and can not solve it: A piece of metallic aluminum weighing 2.50 grams is treated with 75.0 mL of sulphuric acid ( d = 1.18 g/cm3 , 24.7% H2SO4 ). After the metal is dissolved, the solution is diluted to 400mL. a) Calculate the morality of the solution with respect to the...- zpmodel
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- Molarity
- Replies: 1
- Forum: Biology and Chemistry Homework Help
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Solving Parachutist Problem: Force Exerted by Parachute
1. Homework Statement : A parachutist whose total mass is 100kg is falling at 50m/sec when his parachute opens. His velocity drops to 10 m/sec in a vertical displacement of 40m. What force was exerted by his parachute? 2. Homework Equations : F = ma Fg = m(9.8) This is my first...- zpmodel
- Thread
- Parachute
- Replies: 8
- Forum: Introductory Physics Homework Help