Recent content by zstraught

First I use young's modulus to solve for delta y. I get 5.67x10 -5. I am not sure what to do after this, but this is my attempt. Next I do T = 2delta y sqrt(m/k) (I am not sure if I am supposed to put 2 delta y) Solving for f, i get f = 1/(2delta y sqrt(m/k)) F = kx, mg = kx, m = kx/g...

I thought " A 2.4*10^2 N force..." means it is a constant velocity. If it isn't, how would I find the acceleration?

Would it be 0 since it is moving at a constant velocity?

I drew a force diagram, Normal force up, weight down, force of friction to the left, and Force applied 20 degrees above the positive x axis. I need clarification to find the force of Friction for part B. Should I set Force of friction equal to mu · normal force or should I use Newton's second...