Recent content by zxcvzxcv

Hi I understand, I was thinking the same thing. I think I have found the source of the problem: I don't think we can just simply find the complex conjugate by replacing the 'i' with a '-i' because it is in the denominator. If you manipulate the fraction Z =... to get the 'i' on the top...

I'm sorry to not grasp this very simple concept. The value of the capacitor is a fixed quantity, however as I vary the input voltage the capacitance of the circuit varies as roughly a y = c/x function. The equation describes the capacitance as being frequency dependent, should the impedance...

Thank you, I see what I have done wrong. I have now corrected it and have a value of capacitance that varies with frequency - how can I use this to find the value of the capacitor?

The LaTeX in preview post is broken so I don't know how this will come out. My derivation is as follows: - \frac{1}{Z} = \frac{1}{Z1} + \frac{1}{Z2} = \frac{1}{R} + \frac{1}{i \omega C} = \frac{i \omega C}{R i \omega C} + \frac{R}{R i \omega C} = \frac{R + i \omega C}{R i \omega C} Z =...

Thank you, I'm not sure I see how that equation is derived, I will just try to write my own out in LaTeX.

gneil. Thank you very much for your help with this. That must have taken you a long time to write out so clearly. I have learned a lot just reading that through, but I am still digesting everything you have said and will probably have some follow up questions soon. For now, are you (or anyone...

Homework Statement Hi, I have virtually no background in electronics and I have been given the following task. I have to measure the capacitance of the (real) circuit below (using labview, but it is the theory of how to do this that I am interested in). I am not able to use the...