How can a local interaction affect different parts of an atom?

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absolutegod
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how a local interaction coordinate response of spatically separated parts of atom ?
Quantum mechanics says interection coordinate response of atom.

But atom parts i.e electron and nucleus are spatically separated.

However it is treated as one quantum system but been one quantum system doesn't make their distance in between 0.

So, how a local interaction coordinate response of spatically separated parts of atom ?
This is not a homework it is a personal question
 
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You are describing non-relativistic quantum mechanics, the only kind you’ll encounter unless and until you’re well on the way to an advanced degree in physics.

The way NRQM works, we describe the initial state of the entire quantum system with the wave function, the wave function evolves over time according to Schrodinger’s equation, we can calculate the probability of getting various measurement results from the wave function. But that’s all we have, the theory tells us nothing about what the various particles are doing or how they’re interacting.
 
Nugatory said:
You are describing non-relativistic quantum mechanics, the only kind you’ll encounter unless and until you’re well on the way to an advanced degree in physics.

The way NRQM works, we describe the initial state of the entire quantum system with the wave function, the wave function evolves over time according to Schrodinger’s equation, we can calculate the probability of getting various measurement results from the wave function. But that’s all we have, the theory tells us nothing about what the various particles are doing or how they’re interacting.
But I am not saying about wavefuction or outcome .

Want to know,
a photon interacted with atom on electron .

And there is distance between electron and nucleus .

So why will nucleus also response? as there is nothing to make it respond
 
The interactions are described by local field theory. The change at one place creates a local change in the field, after which this change propagates to other places through the field. The speed of propagation does not exceed the speed of light.
 
absolutegod said:
But I am not saying about wavefuction
You cannot avoid wavefunctions. When you are talking about QM, wavefunctions will necessarily be involved.

absolutegod said:
So why will nucleus also response?
The wavefunction is spread out over space. Generally it will be non-zero in both the region of the electron and the nucleus. Both will therefore respond to the wavefunction according to the usual QM rules.
 
Demystifier said:
The interactions are described by local field theory. The change at one place creates a local change in the field, after which this change propagates to other places through the field. The speed of propagation does not exceed the speed of light
Thank you for answer

But my question is not about result or outcome

It is about :
How a local interaction at electron coordinate response of spatically separated nucleus during photon interaction.
 
Dale said:
You cannot avoid wavefunctions. When you are talking about QM, wavefunctions will necessarily be involved.

The wavefunction is spread out over space. Generally it will be non-zero in both the region of the electron and the nucleus. Both will therefore respond to the wavefunction according to the usual QM rules.
If wavefuction is spread all over continuously .
then how we can say atom is in supper position?

As wavefuction is continuously present and acting on it. Somthing like this interaction also do .

And if atom can be in superposition when wavefuction is present .

How will wavefuction coordinate it to become measurable from supper position ?
 
absolutegod said:
If wavefuction is spread all over continuously .
then how we can say atom is in supper position?
In what way is there any conflict between a wavefunction being spread out and an atom being in superposition?

absolutegod said:
How will wavefuction coordinate it to become measurable from supper position ?
Again, what is the supposed conflict between superposition and the wavefunction?

There simply isn’t any conflict between them as far as I know, and I cannot guess why you think there might be. Please explain.