Equation for half-max contour of 2D Gaussian?

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Discussion Overview

The discussion revolves around finding the equation for the elliptical contour line at half-max of a two-dimensional Gaussian function. Participants explore the mathematical formulation and implications of the Gaussian parameters.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the Gaussian equation G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b and asks for the equation of the half-max contour.
  • Another participant questions whether the original poster has calculated the maximum value and considered using half of that in their equation.
  • A participant expresses a desire for a standard result to avoid deriving the equation from scratch.
  • A later reply suggests that G(x,y) = h/2 leads to the equation (x-x0)^2/a + (y-y0)^2/b = ln(2) for the half-max contour.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the approach to derive the half-max contour equation, and there are multiple viewpoints regarding the necessity of deriving it versus using known results.

Contextual Notes

Some assumptions about the parameters and their values are not explicitly stated, and the discussion does not clarify the derivation steps leading to the proposed equation.

mikeph
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Hi all,

If I have a Gaussian with the equation:

G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

I'm getting myself confused!

Thanks for help
 
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MikeyW said:
G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)
what's the equation for the elliptical contour line at the half-max of G?
How far did you get? Did you find the max value? Did you plug half that into the equation to see what resulted?
 
I was wondering if there is some standard result that meant I didn't have to do all that.
 
MikeyW said:
Hi all,

If I have a Gaussian with the equation:

G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

I'm getting myself confused!

Thanks for help
G(x,y) = h/2 is what you want.

(x-x0)2/a + (y-y0)2/b = ln2.
 

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