Solve the Stone Drop Problem: Acceleration of 9.8m/s^2

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SUMMARY

The discussion centers on solving the Stone Drop Problem involving a stone dropped from a height of 122.5 meters with an acceleration of 9.8 m/s². The solution requires breaking the problem into two distinct parts: calculating t1, the time for the stone to fall, and t2, the time for the sound to travel back up the shaft. The total time is the sum of t1 and t2, providing a comprehensive approach to the problem.

PREREQUISITES
  • Understanding of kinematic equations, specifically for free fall.
  • Knowledge of sound speed in air, approximately 343 m/s at room temperature.
  • Familiarity with basic algebra for solving equations.
  • Concept of time of flight in physics.
NEXT STEPS
  • Calculate the time of free fall using the equation t1 = √(2h/g), where h is the height and g is the acceleration due to gravity.
  • Determine the time for sound to travel using the formula t2 = distance/speed, where distance is the depth of the shaft and speed is the speed of sound.
  • Explore the effects of air resistance on falling objects for more complex scenarios.
  • Investigate real-world applications of kinematic equations in engineering and physics.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion and sound in a practical context.

emma123
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i need help on the following problem:
"carol drops a stone into a mine shaft 122.5 m deep. How soon after she drops the stone does she hear it hit the bottom of the shaft?"
i know that the acceleration is 9.8m/s^2 but i can't use it as speed in the speed=distance/time equation
please help me. thanx
 
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Break the problem into two parts.

Calculate t1, the time it takes the stone to fall from her hand to the bottom of the well.

Then find t2, the time it takes the sound to travel from the bottom of the well to the top.

The total time is just t1 + t2.
 

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