Photons that orbit at the event horizon.

In summary: The velocity of propagation of electromagnetic energy has been postulated to remain constant in vacuum or free space, per Mr. Einstein, to all observers, but only the relativistic energy of the electromagnetic wave depends on the relativistic dynamics of the frame of reference of the observer, and can in theory range from zero to infinity (without any limiting laws ).
  • #1
Primordial
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0
My question is: Photons that orbit at the event horizon, require relativistic time to circumvent the circumference of the black hole relative to an observer external to the black hole, keeping Mr. Einsteins second postulate in mind, that being the velocity of light is constant through vacuum ( or free space), and keeping in mind, dilated space-time is considered free space or in vacuum. What is the relativistic time required for the photon to complete one revolution at the event horizon, relative to an external observer of the black hole, would it be the same as the time required light to travel an equivalent distance as observed in free space external to the black hole, or would it take a much longer relativistic time?
 
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  • #2
Primordial said:
My question is: Photons that orbit at the event horizon, require relativistic time to circumvent the circumference of the black hole relative to an observer external to the black hole, keeping Mr. Einsteins second postulate in mind, that being the velocity of light is constant through vacuum ( or free space), and keeping in mind, dilated space-time is considered free space or in vacuum. What is the relativistic time required for the photon to complete one revolution at the event horizon, relative to an external observer of the black hole, would it be the same as the time required light to travel an equivalent distance as observed in free space external to the black hole, or would it take a much longer relativistic time?

Photons don't orbit at the event horizon, they orbit on the photon sphere at a (coordinate) distance of 1.5 that of the event horizon.
 
  • #3
George Jones: Would the existence of the photon sphere, being outside the event horizon, prevent protons between the photon sphere and the event horizon, escaping the black hole?
 
  • #4
Primordial said:
George Jones: Would the existence of the photon sphere, being outside the event horizon, prevent protons between the photon sphere and the event horizon, escaping the black hole?

No. If a hovering laser located between the event horizon and the photon is fired within a certain range of directions, its light will escape the black hole. For lasers located closer and closer to the event horizon, the range of directions becomes more and more restricted.
 
  • #5
Thank you for your answers, they fit very well.
 
  • #6
George Jones said:
No. If a hovering laser located between the event horizon and the photon is fired within a certain range of directions, its light will escape the black hole. For lasers located closer and closer to the event horizon, the range of directions becomes more and more restricted.
As the laser's direction varies, some photons escape, some do not. So what happens at the borderline between those two possibilities? Naively I might expect photons to orbit at that borderline angle, but I have heard this is not possible.
 
  • #7
DrGreg said:
As the laser's direction varies, some photons escape, some do not. So what happens at the borderline between those two possibilities? Naively I might expect photons to orbit at that borderline angle, but I have heard this is not possible.

The border is orbit on the photon sphere!

When [itex]c=G=1[/itex], the event horizon is at [itex]r=2M[/itex] and the photon sphere is at [itex]r=3M[/itex]. Suppose the laser hovers at any [itex]r>2M[/itex], and let [itex]\phi[/itex] be the firing angle with respect to vertically up, in the laser's frame. When

[tex]
\sin\phi = \sqrt{3} \frac{3M}{r} \sqrt{1 - \frac{2M}{r}},
[/tex]

the light will asymptotically approach orbit on the photon sphere as [itex]t \rightarrow \infty[/itex].

Note that as [itex]r \rightarrow 2M[/itex], [itex]\phi \rightarrow 0[/itex], and that as [itex]r \rightarrow 3M[/itex], [itex]\phi \rightarrow 90[/itex] degrees.

If you want, you can try

https://www.physicsforums.com/showthread.php?p=1091901#post1091901

For example, I was just playing with [itex]r=38[/itex], [itex]v=1.0[/itex], which results in a border angle (with respect to horizontal) of

[tex]
\cos^{-1} \left( \sqrt{3} \frac{45}{38} \sqrt{1 - \frac{30}{38}} \right) = 19.760326661 \mathrm{ degrees}.
[/tex]
 
  • #8
George Jones: I appreciate your help and suggestions, however my original thought was not very well composed, so I will try again, I have noticed that the velocity of propagation of electromagnetic energy has been postulated to remain constant in vacuum or free space, per Mr. Einstein, to all observers, but only the relativistic energy of the electromagnetic wave depends on the relativistic dynamics of the frame of reference of the observer, and can in theory range from zero to infinity (without any limiting laws ) and not the velocity of the electromagnetic wave. I use this concept to explain to myself the reason the photon can not escape the black hole and allows the gravitational boson to have the ability to mediate its interaction with space-time outside the black hole, from within the black hole. I would like to know if there is, a better explanation in the world of physics? Hope you can help.
 
  • #9
George Jones : One of the most basic questions about the Schwarzschild radius on my mind is, was the premise of Mr. Schwarzschild equation based on the escape velocity of the interaction of photon boson, or on the premise of the relativistic energy content of the photon boson reaching null geodesics.
 
  • #10
Black holes can have electrical charge as well as mass. Consequently, a black hole can interact electromagnetically (attraction or repulsion) with a charged particle outside the black hole's event horizon. Read D.08 and D.08 of the FAQ

http://sciastro.astronomy.net/sci.astro.4.FAQ
 
Last edited:
  • #11
George Jones : Thank you for your reference, this problem first came to me while I was in college in Texas, I managed to speak to several Professors, each of which indicated another that was more knowledgeable than the previous, until I was introduced to a Dr. Remler from the University of Texas dept. of Relativity, whom at the time was presenting a theory of his pertaining to the visible edge of the Universe, he referred to his concept as Horizons. He told me, I had a great imaginative mind. He liked some of my concept.
 

1. What are photons that orbit at the event horizon?

Photons that orbit at the event horizon are particles of light that are caught in the gravitational pull of a black hole and are trapped in a circular orbit around the black hole's event horizon, the point of no return.

2. How are these photons able to orbit at the event horizon?

These photons are able to orbit at the event horizon because of the extreme gravitational force exerted by the black hole. This force is so strong that it can bend the path of light and cause it to orbit around the black hole.

3. Can these photons escape from the event horizon?

No, these photons cannot escape from the event horizon. Once they are caught in the gravitational pull of the black hole, they are trapped and cannot escape. However, they can still provide valuable information to scientists about the black hole's properties.

4. How do scientists study these photons that orbit at the event horizon?

Scientists study these photons by using telescopes and other instruments to observe the radiation emitted from the particles as they orbit the black hole. This radiation can provide insights into the behavior and structure of the black hole.

5. What is the significance of studying these photons at the event horizon?

Studying these photons at the event horizon can help scientists better understand the properties of black holes, such as their mass, spin, and accretion rate. It can also provide insight into the behavior of matter and energy in the extreme conditions near a black hole.

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