How to find the Tension in a support cable?

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Homework Help Overview

The discussion revolves around determining the tension in a support cable for a wrecking ball system, involving forces acting on a boom and the associated angles. Participants are exploring the mechanics of forces and torques in this context.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss setting up free body diagrams (FBDs) and applying equilibrium equations for vertical and horizontal forces, as well as moments. There is confusion regarding the correct application of angles and the tension formula.

Discussion Status

Some participants have shared their setups and calculations, while others are questioning the assumptions made about angles and the direction of tension. Guidance has been offered regarding the resolution of forces and moments, but no consensus has been reached on the correct approach or calculations.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is uncertainty about the angles involved and the correct application of tension in the context of the problem.

MKM
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A wrecking ball (weight = 5910 N) is supported by a boom, which may be assumed to be uniform and has a weight of 2820 N. As the drawing shows, a support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32°, and the angle between the boom and the horizontal is 48°. Find (a) the tension in the support cable and (b) the magnitude of the force exerted on the lower end of the boom by the hinge at point P.
I have been having trouble trying to finf the tension, not sure how I originally thought to just do the sum of the torques but it's not coming out. I thougit was just T = 3/4 sin 90 ? very confused?
 

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Last edited:
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You need to construct a FBD, then do,

ΣFv = 0
ΣFh = 0
ΣM = 0

where M is a moment, or torque.
 
This is how I set up my equation Torque sum =
-2820N (L/2)sin 138
+ T(3/4)L sin 90
- 5910sin138 =0 and I get 6530 ?
What I realized later was that I think I'm supposed to use the 32 angle for the tension force in some way but I'm not sure. I hope m attachment isn;t pending for very long it's a good description
 
I think I have an idea of what your attachment will look like.
Is it like mine ?

http://img476.imageshack.us/img476/4256/mkm10sa.jpg

If so, then the FBD could be something like my 2nd attachment

http://img476.imageshack.us/img476/5760/mkm26qe.jpg
 

Attachments

  • mkm1.jpg
    mkm1.jpg
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  • mkm2.jpg
    mkm2.jpg
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Last edited by a moderator:
wow It's exactly like your second attachment . I actually had the Tension facing outward perpendicular to the support cable but maybe I was wrong.
 
MKM said:
wow It's exactly like your second attachment . I actually had the Tension facing outward perpendicular to the support cable but maybe I was wrong.

Tension is always in the direction of the cable (or whatever else is providing the tension).
 
okay I have evrything set up but I dont; understnad how to aply the tension formula which I think is T= mv squared/ L. Also when I am looking for the sum of the torques should I just add the tension to the other forces and find Rx and Ry?
 
MKM said:
okay I have evrything set up but I dont; understnad how to aply the tension formula which I think is T= mv squared/ L. Also when I am looking for the sum of the torques should I just add the tension to the other forces and find Rx and Ry?
I don't understand your tension formula. What is the v ? There is no velocity involved.

Do what I suggested in my first post. Do a balance of forces, both horizontal and vertical. Then do a balance of moments (or torques).

ΣFv = 0
ΣFh = 0
ΣM = 0

When doing the sum of torques, Pick a point, A say, and take the moments of every force about this point. All the forces are listed in Fig2. Remember that the tension T, in Fig2, should be ignored since it has been resolved into horizontal and vertical components, Tcos32 and Tsin32 respectively. And it is these two forces that should have their moments taken, not T.
 
should the angle between the boom and the cable be 48-32=16?
 

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