How to Determine the Uncertainty of Q.total?

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SUMMARY

The discussion focuses on calculating the uncertainty of the total charge (Q.total) in a circuit with two capacitors in series, specifically C1 (1019 microFarads) and C2 (553 microFarads), with voltage values of V1 (3.58 volts) and V2 (6.56 volts). The individual charges are calculated as Q1 (3648 Coulombs) and Q2 (3627 Coulombs), with variances of 186 and 185, respectively. To find the total charge, the formula Q.total = C.eq * V.total is applied, yielding a total charge of 3634.84 Coulombs. The uncertainty of Q.total can be determined using the variance propagation formula, Var(Q) = dQ/dA * Var(A) + dQ/dB * Var(B).

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Problem 1
Given: 2 capacitors in a series, each capacitor's farad & voltage across.
Voltage uncertainty 1%, capacitor uncertainty 5%
C1: 1019microFarads C2: 553microFarads
V1: 3.58 volts V2: 6.56 volts
Uncertainty: 5% for CAPs & 1% for Volt

Find Q for each: Q1=3648 Coulombs Q2=3627 Coulombs
Find Q's +/-(variance): SQRT(.05^2 + .01^2) = .051
Q1 Variance: 186 Q2 Variance: 185


Now for the question:
find Q.total Q.total=C.eq * V.total => 3634.84
What is the Uncertainty of Q.total??


Does anyone know how to find Q.total's variance?
I've looked through my text and online, still no luck.

If anyone could make a suggestion, I'd be very appreciative.


Thanks
 
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Hmm.. you should consult a book on statistics. I think that Gauss proved something about how to calculate the variance.

For example, if you have the formula Q = A * B and you know the variances of A and B, then the variance of Q can be calculated. If I am not mistaken you find it with
Var(Q) = dQ/dA * Var(A) + dQ/dB * Var(B)
and this formula applies generally.

I might have confused the variance with the standard deviation or something so there might be a squareroot over the whole right hand side...
 

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