Pressure, Buoyant Force problem

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Homework Help Overview

The problem involves a solid cube of unknown material floating in water, with a portion of the cube above the water's surface. The objective is to determine the density of the cube based on its buoyancy and the principles of fluid mechanics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the buoyant force and the weight of the cube, with one participant attempting to calculate pressure and force using given equations. Others explore the density ratio and the implications of their calculations.

Discussion Status

The discussion includes attempts to clarify calculations and assumptions regarding buoyancy and density. Some participants express confusion about their results and seek explanations for discrepancies in their answers. Multiple interpretations of the problem are being explored without a clear consensus.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is also a noted uncertainty regarding the accuracy of calculations and the interpretation of results.

ChunkymonkeyI
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Homework Statement


A solid cube of unkown material is floating upright in water so that 1/4 of the cube is above the surface of the water. What is the density of the material?


Homework Equations


Density=m/v
F=mg
Fb=density of fluid times volume of the fluid times g
P=density times height times g

The Attempt at a Solution


Since the cube is floating upright in the water I think that means that the force of weight is equal to the buoyant force.
P=density times h times g
P=1000 kg/m^3 times 1/4 times 9.80 which equals 2450 Pa
Then I used F=PA
F=2450 Pa times 1/4 which equals 612.5 N
Then I used F=mg
m=F/g
m=612.5 N/9.80 m/s^2
m=62.5 kg
I don't know what 2 do from there and I think one of my step is wrong because I multiplied the area by 1/4 but I don't think that's right can someone please help me and explain 2 me how to solve this problem
 
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(Density of the object / density of the fluid) x 100 = Prencentage of object's volume in the fluid
 
But when I do that I get the following:
b/1000 kg/m^3 times 100=3/4
100b/1000=3/4
1b/10=3/4
b=7.5 and b is the density of the object but on my sheet it says the answer is 750 kg/m^3 and its almost like my answer but the decimal is moved over and idk y. Maybe my work was wrong or something can u explain ?
 
hmzone said:
(Density of the object / density of the fluid) x 100 = Prencentage of object's volume in the fluid

But when I do that I get the following:
b/1000 kg/m^3 times 100=3/4
100b/1000=3/4
1b/10=3/4
b=7.5 and b is the density of the object but on my sheet it says the answer is 750 kg/m^3 and its almost like my answer but the decimal is moved over and idk y. Maybe my work was wrong or something can u explain ?
 
3/4=0.75 is not the Precentage dude, it's 75%
 

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