Common perpendicular of two lines

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SUMMARY

The discussion focuses on finding the common perpendicular between two lines represented in 3D space. The lines are defined by the equations x / 2 = (y-1) / 2 = z and x + 1 = y – 2 = (z + 4) / 2. The direction vectors for these lines are V1 = (2, 2, 1) and V2 = (1, 1, 2). The cross product of these vectors, calculated as V1 X V2 = (3, -3, 0), confirms the correctness of the approach to determine the common perpendicular.

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ydan87
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Hi there,
The two given lines:
1) x / 2 = (y-1) / 2 = z
2) x + 1 = y – 2 = (z + 4) / 2
I need to find the common perpendicular between them.
Though when I tried to calculate the distance between them, I get 0.

Can someone please help?

Thanks in advance
 
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Think about the cross product of their direction vectors.
 
Easier than I thought! Thanks :)
 
Direction vectors of lines 1 and 2: V1 = (2, 2, 1), V2 = (1, 1, 2)
V1 X V2 = (3, -3, 0)

Is it correct?
 
Yes, it is.
 

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