AxiomOfChoice
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- 1
I'm guessing that if z\in \mathbb C, then we have
<br /> \left| z^{-1/2} \right|^2 = |z^{-1}| = |z|^{-1} = \frac{1}{|z|}.<br />
Proving this seems to be a real headache though. Is there a quick/easy way to do this?
<br /> \left| z^{-1/2} \right|^2 = |z^{-1}| = |z|^{-1} = \frac{1}{|z|}.<br />
Proving this seems to be a real headache though. Is there a quick/easy way to do this?