arrhenius equation Definition and 19 Threads

Hello, I have a doubt in a question from a chemistry MIT course: My attempt is attached. The formula given in the lecture is D = Do * exp(-Ea + Delta Gn)/RT However, they don't explain what Delta Gn is, I suppose it is Gibbs free energy, but as the statement doesn't give any other extra energy...

Homework Statement A reaction has a rate constant of 0.0117/s at 400.0 K and 0.689/s at 450.0 K. What is the value of the rate constant (to 1 decimal place) at 538 K? Homework Equations ln k= ln A-E[a]/RT The Attempt at a Solution I'm not sure how to approach this problem, although I know...

Hey, I'm doing an experiment where I run a reaction at three different microwave powers to determine if there is any effect beyond the standard temperature ramp rates. If I know how long it takes the reaction to go from 260 C to 280 C in each of these cases, is there any possible way to extract...

I know the Arrhenius equation is k=Ae^-Ea/RT The rate constant k is directly proportional to 1/t (t stands for the time for the reaction to reach a point) So I wonder if we can substitute k by 1/t in the Arrhenius equation to become 1/t=Ae^-Ea/RT ? Thanks a lot

I wanted to see how the rate of change of rate constant with temperature (dk/dT) changes with activation energy. I tried to do this with differentials: k=A*e-EA/RT so \frac{dk}{dT} = \frac{A E_A \cdot e^{-\frac{E_A}{RT}} } {RT^2} and then \frac{d(\frac{dk}{dT})}{dE_A} = A \cdot...

This is part of a lab report so not sure if the template agrees with what I am asking but basically using the Arrhenius equation in the form of ln(k)=ln(A)+(\frac{-E_a}{R})(\frac{1}{T}) I plotted a straight line graph of ln(k) vs 1/T and found the gradient to be -5525. Its the units that are...

Hello, I am curious as to how the Universal Gas Constant, R, is important with regards to the rates in solids? It is in the Arrhenius Equation

Homework Statement For the two parallel reactions ##A \stackrel{k_1}{\rightarrow} B## and ##A \stackrel{k_2}{\rightarrow} C##, show that the activation energy ##E'## for the disappearance of ##A## is given in terms of activation energies ##E_1## and ##E_2## for the two paths by...

When finding the activation energy, which equation is the correct one: ln(k2/k1)=-Ea/R * (1/T2-1/T1) or ln(k1/k2)=Ea/R * (1/T2-1/T1) Notice k1/k2 in the second equation. As well as the -Ea instead of Ea Thanks

They both are derived from same kinetic theory of gases, but I've heard that eyring polanyi equation is more advantageous over the arrhenius equation. Why do you think that is the case?

Hi there I've been trying to work this out and didn't quite succeed, so I'm hoping someone might help me out a bit. I've been using the Arrhenius equation to calculate reaction rates at 2 temperatures, so I took the integral and got k2/k1 = e^(Ea/R(1/T1 - 1/T2)) This paper I've been...

This may be a pretty dumb question, but how is it that as the exponent value of e decreases, the rate k increases? This seems counter-intuitive, and when I enter values for e into my calculator and compare them, the higher exponents (e.g. 50 vs. 20) give higher results.

Homework Statement This isn't a homework question but this thing is disturbing from a long time. I attended a class on Arrhenius equation and its plots. One of the plots is disturbing me from long which is the plot between k vs T. Arrhenius equation:- k=Ae^{-\frac{E_a}{RT}} k->Rate constant...

Homework Statement At what temperature does K = A? Homework Equations k= Ae^{-Ea/RT} The Attempt at a Solution In order for K to equal A, then e=0. But at what temperature can e=0? The temperature can't be 0, because that would be impossible. Any help is appreciated?

Chemistry- two point Arrhenius Equation (miscalculation??) Homework Statement At 25 degrees celsius, the first-order rate constant for a reaction is 2.0 x 10^3 s^-1. The activation energy is 15.0 kJ/mol. what is the value of the rate constant at 75 degrees celsius. T1= 298.15 K T2=...

Hello everyone, I am having trouble with determining where I erred in the following exercise. If someone could point out my mistake, I would appreciate the help. Thank you! --- 1. The decomposition of N2O5 has an activation energy of 103 kJ/mol and a frequency factor of 4.3E13 s^-1 . What...

Homework Statement The activation energy for the reaction N2O(g) --> N2(g) + O(g) is 250 kJ/mol. If the rate constant is 3.4 s–1 at 1050 K, at what temperature will the rate constant be one thousand times smaller? The correct answer is : 846 K Homework Equations Arrhenius equation...

Homework Statement A common rule of thumb is that temperature 10 degrees C for many reactions will double the reaction rate. Derive under what conditions this is true.Homework Equations ln(k) - ln(2k) = (-Ea/R) [(1/T1)-(1/T2)]The Attempt at a Solution I know I have to start off by plugging in...

Homework Statement A certain reaction, with an activation energe of 64.5 kJ/mole, is run at 25.0'C (degree Celsius) and its rate is measured. How many times faster would this reaction be if it were run at 50.0'C (degree Celsius)? Homework Equations I think: (Arrhenius equation)...