Clausius clapeyron problem - i have spent 3 hours on this problem

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Homework Help Overview

The discussion revolves around a problem related to the Clausius-Clapeyron equation, specifically focusing on finding the change in transition temperature given certain parameters such as pressures, temperatures, enthalpy, and densities of two metals. The original poster expresses frustration after spending considerable time on the problem without arriving at a solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate the change in transition temperature to the Clausius-Clapeyron equation but struggles with how to incorporate the provided densities and atomic weights into their calculations. They question how to find the change in volume given the two densities and express confusion about the relevance of these values.

Discussion Status

Some participants have provided insights regarding the use of densities and the nature of solids in relation to the ideal gas law. There is ongoing exploration of how to calculate the change in volume and the implications of using two different densities. The discussion remains open with various interpretations being considered.

Contextual Notes

The original poster notes that the problem is unique in its request for the change in transition temperature, which has not been commonly encountered in similar examples. They also highlight the challenge posed by the presence of two densities and the need to understand their application in the context of the problem.

rwooduk
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spent 3 hours on this, getting nowhere

find the change in transition temperature, given: P1,P2,T1,ΔH,density (mixed so gives d1 of metal 1 and d2 of metal 2,atomic weight

Clasius-Clapeyron-Equation.gif


Tried solving for T1 then for ΔT simply saying ΔT = (T1 - T2) , but its clearly not correct and i haven't made use of the densities or the atomic number the question gives.

So then i approximated the problem fromt he original clausius clapeyron eqn to

ΔP/ΔT = ΔH / (TΔV)

but then to find ΔT, which i assume is the change in transition temperature, i need ΔV

so i did density = m/v , PiVi = nRTi to give density = PM / RTi where M is the molar volume

but the density would change with the pressure, so how am i supposed to use the initial density, and there's two densities not one for the compound??

I guess what I'm asking is how do i find ΔV given the above data? why have i been given the two densities of the compound when the densities are going to change with pressure?


Ive spent 3 hours on this question, looked for similar examples on the internet, there are NONE. General questions ask for T2 or P2, none ask for the change in transition temperature.

Please help, erghhhhh, i better get on with my maths now
 
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You used the ideal gas law, but metal solids don't obey the ideal gas law. That's why you were given the densities. The density is the inverse of the specific volume, and, for metal, the density has negligible change with temperature and pressure (at least as far as your application is concerned).
 
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i see, thanks for the reply, i understand density = 1 / volume per unit mass, but i still need to find the change in volume (however small) somehow from the 2 densities.
 
rwooduk said:
i see, thanks for the reply, i understand density = 1 / volume per unit mass, but i still need to find the change in volume (however small) somehow from the 2 densities.

So what are the two densities? Why can't you do it?
 
hi, because the volume before would not be the same as the volume after, even though there is a negligable change in volume i need that change to give me delta V, in order to plug it into the clausius clapeyron eqn to give delta t.


and what do i do with the two densities, take an average of the two?

and why has it given the atomic weight?
 
Last edited:
just to update this, the question wanted the MOLAR VOLUME
 

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