A seesaw (also known as a teeter-totter or teeterboard) is a long, narrow board supported by a single pivot point, most commonly located at the midpoint between both ends; as one end goes up, the other goes down. These are most commonly found at parks and school playgrounds.
Hi everyone! I am not a physicist or a physics student. Just a simple video game programmer. I have recently gotten into a discussion with my fellow programmer about a specific hypothetical problem regarding levers. The problem might seem very simple at first, but cause me a bit of headache...
Men is at seesaw , connected with rope to beam which is conected to seesaw with joint,when fan is off ,seesaw is stay at brawn box.
When you turn ON fan,man and beam are in balance,can seesaw flip to right side?
(If beam is conect with fixed conect to seesaw then for sure it will flip to right...
I drew a diagram for the a) part
The person is h meters high
So GPE= 100 x 9.8x h
GPE= 980h j
KE = 980h when the person hits the see saw
KE=1/2mv²
980h=0.5 x 5 x v²
Now it v²=u²+2as
For the brick going up to 10m
v = 0
u=?
a=-9.8ms-²
s=10m
u²=2 x 9.8 x 10
u=14m/s
We can assume that u=14m/s is...
Homework Statement
The fulcrum of a uniform 20-kg seesaw that is 4.0 m long is located 2.5 m from one end. A 26-kgchild sits on the long end.
Determine the mass a person at the other end would have to be in order to balance the seesaw.
Homework Equations
Torque = force x distance from...
Here's a question that I've been trying to solve for a while but keep on running into dead ends, and I can't seem to find any info on the internet to help me. Anyways I was wondering what the integral of torque is? For my specific example I have a rod that is not equally balanced on a fulcrum...
I have just started reading about neutrino physics and recently came across two terms called double seesaw and singular seesaw. Although I’m familiar with other seesaw mechanisms (such as type-I and II) for explaining smallness of neutrino mass. I’m completely at dark about double and singular...
Homework Statement
Okay, so I am doing a physics investigation and I am supposed to have a theory I can test. I have a catapult I made myself, and I change the force exerted on the rod of the catapult by changing the mass that hangs by a string. It is a seesaw with a hinged mass on one end.
I...
I know the seesaw mechanism is a model used to explain both neutrinos having mass and why their dirac mass/yukawa coupling is so much smaller than for the other fermions.
The seesaw mechanism needs the right handed neutrino to exist. How does the seesaw mechanism for the vMSM differ from that...
ok so this is a bit of a boring question, so sorry in advance, but for some reason I am struggling with this.
I am deriving the seesaw formula.
Now I have gone through the derivivate and I get A : ## m_{\nu} = - m_D^T M^{-1} m_D ##
Now I have seen other derivations where they get B ...
Homework Statement
Describe the relationship between the resulting torque from each scenario using the torque equation.
Question this question is addressing- Using the bricks from the materials on the right, create and record 10 different combinations of two unequal masses that result in a...
I'm trying to get my story straight on explaining the universe's matter-antimatter imbalance.
So far I understand CP violation in neutrino oscillations (PMNS \delta parameter). And I think I'm right in saying that then a 'leptogenesis' process generates an excess of leptons over antileptons...
Hi
Since a few days I've been confused about the seesaw mass matrix explaining neutrino masses. It is the following matrix:
\begin{pmatrix} 0 & m\\ m & M \\ \end{pmatrix}.
As can easily be checked it has two eigenvalues which are given by M and -m^2/M in the limit M>>m (the limit doesn't...
Homework Statement
This isn't homework but I don't know where to post this type of questions so I will post it here.
But, I am wondering what are the physics equations that describes the system of a candle that is lit and behaves like a seesaw?
I have attached an image.
Explanation:
A...
Hi all,
I think it's just an Eigenvalue preoblem. I'm studying Seesaw mechanism from
http://www.quantumfieldtheory.info/TheSeesawMechanism
I don't get how he substituted in equ. 21 for N Eigenvalue from equ. 20, that ## \frac{m_D}{m^R} ## is a factor of ## \nu_R ## not ## \nu_l^c ## ? Any help ..
Homework Statement
A seesaw with a mass of 5 kg has one block of mass 10 kg two meters to the left of the fulcrum and another block 0.5 m to the right of the fulcrum. If the seesaw is in equilibrium,
A. find the mass of the second block.
B. find the force exerted by the fulcrum
I have trouble...
this isn't really a homework question but this seems the most appropriate area since i feel the mechanics involved is fairly simple.
i was absent mindedly considering a seesaw with two equal masses at either end of a massless arm and the fulcrum in the middle of the arm.
in this scenario if...
Homework Statement
It's a balanced seesaw but the pivot isn't in the exact middle and two weights are on it. One at the very end of each side.
The weight on the left is 4.8 kg.[m1]
The weight on the right is 5.5 kg[m2]
The length of the entire seesaw is 5m
L1 is the distance from the...
Three people are balanced on a uniform seesaw -- Torque
Homework Statement
Three people are balanced on a uniform seesaw which has a weight of 150 N as shown in the figure.
Find the mass of person B and the normal force acting on the fulcrum.
Homework Equations
Tcw=Tccw
The...
Homework Statement
A large wooden beam weighs 820 N and is 3.2 m long. the beam's CG is 1.4 m from one end. two workers carry it away. If they lift the beam at its ends, what part of the weight does each worker lift?
Homework Equations
Tcw=Tccw
F*l=F*l
The Attempt at a Solution
I...
Hi
I thought if there is a heavier person and a lighter person the heavier person would sit nearer the fulcrum to make the seesaw balance as weightxlength must equal. However on this question 'which picture shows how the two boys will balance better?' the answer is the one with the bigger...
Hi all. A friend and I were discussing whether or not it was possible to construct a mechanism of weights and pulleys etc. or other methods to keep a seesaw level regardless of where the weight was placed on the platform. The end result would be the ability to step onto one side of a level...
I was watching an old episode of MythBusters, and the myth they tackled was the Seesaw Saga. It's about a sky diver hitting a seesaw and launching a girl on the other end high into the air. I immediately noticed that MythBusters had no idea how momentum transfer on a seesaw works, which isn't...
Let's say i have a plank of wood (seesaw) 2in x 8in x 12ft with approx. mass of 50lbs. The fulcrum is 2.36ft high and is in the center of the board. There is 45lb placed on one end and 22 lb place on the other end. The 22lb end is secured to the ground ready for release. The 45lb-end is 4ft...
Homework Statement
Halle and Susan, each of mass 40 kg are sitting at opposite ends of a playground seesaw. The seesaw is stationary in the horizontal position and is 4.50 m long. Susan decides to jump off. Calculate the size of the unbalanced torque that now acts on the seesaw.
Homework...
This is not homework, it is purely for my own enjoyment.
Say I have a lead sphere with a one meter radius, a mass of 465800N and a terminal velocity of 1290m/s. Say I also have a different spherical body of 685N. I now place the 685N body on one side of a seesaw of 20m in length and a height...
Homework Statement
A 442.3 N person and a 286.1 N person sit on either end of a 2.65 m long seesaw. Where along the seesaw should the pivot point be placed to ensure rotational equilibrium?
Homework Equations
F=ma
The Attempt at a Solution
442.3x=286.1(2.65-x)...
Homework Statement
http://img713.imageshack.us/img713/9151/screenshot20110501at113.png Homework Equations
Angular acceleration = Torque/Inertia
Torque = Fd
Mass_moment_Inertia=mr^2
The Attempt at a Solution
->assume masses on the end of seesaw are point particles for calculating inertia. is...
I want to write a program that basically mimics the physics of seesaws. Part of a project I'm working on. I understand how equilibrium works and everything, but let's say that I have a mass on each end of the seesaw, and both masses are equal distance from the pivot. If both masses have the...
CORRECTION ON TITLE: it should be "Rotational Inertia Seesaw Pivot"Homework Statement
Alice (20kg) and Bonnie (25kg) sit on seesaw (10m long, 12 kg mass). Pivot of seesaw is in the middle. In order for the seesaw to stay level we determined (in the previous step of the multi-part problem)...
Homework Statement
Two children are sitting on opposite ends of a uniform seesaw of negligible mass, if a 35 kg child is 2.0 m from the pivot point, how far from the pivot point will her 30 kg playmate have to sit on the other side for the seesaw to be in equilibrium. please help
Homework...
case 1: Seesaw is balanced with its fulcrum point or pivotal point. At one end of seesaw, the spring (with spring constant K1) is attached. Now the seesaw has total mass M which is attached to spring, form a spring-mass system. I confuse on this point that the oscillation of seesaw will be...
please help me to find differential equation of spring-mass system attached to one end of seesaw.
case 1: Seesaw is balanced with its fulcrum point or pivotal point. At one end of seesaw, the spring (with spring constant K1) is attached. Now the seesaw has total mass M which is attached to...
Homework Statement
Describe how one could find the weight of some unmarked object using only a stick of known weight. Assume that the unknown weight can be attached to the stick and that we know about torques and centers of mass.Homework Equations
I'm not sure this seems to be my problem...
Homework Statement
Three children are trying to balance on a seesaw, which includes a fulcrum rock acting as a pivot at the center (x = 0), and a very light board 5.2 m long (see figure). Two playmates are already on either end. Boy A has a mass of 50 kg, and boy B a mass of 35 kg. Where...
Homework Statement
There is a seesaw. The pivot point is closer to the left side than the right side. Let`s call the left length of the beam L1 and the mass on the left side m1. The right sideof the beam is L2 and the mass is m2. Information is L1 = 0.990 m, L2 = 1.78m, m1 = 4.40 kg, and m2...
Three boys are trying to balance on a seesaw, which consists of a fulcrum rock, acting as a pivot at the center, and a very light board L = 3.52 m long, see figure below.
Two boys are already on either end. One has a mass of m1 = 53.0 kg, and the other a mass of m2 = 32.8 kg. How far from the...
Homework Statement
Two children balance on a seesaw. One, with a mass of 30 kg, is seated 2.0 m from the pivot. The other is seated 2.5 m from the pivot. What is the mass of the second child?
Homework Equations
N/A
The Attempt at a Solution
I drew the diagram of the two children...
When I do some physics derivation, I find that on a seesaw, if the object is farther away from the fulcrum, the angular acceleration decreases. Is this true? If not, where did I go wrong?
\tau = I \cdot \alpha
\tau=F \cdot r
Then, \alpha = \frac{F \cdot r}{I} = \frac{F_g \cdot r}{mr^2}=\frac{g...
1. Homework Statement
A child weighs 34 Kg is seated on a seesaw. While a child who weighs 40 kg is situated on the opposite end of the seesaw. The function B(x)= 34x / 40 gives the distance that the 40 kg child must sit from the center of the seesaw when the 34 kg child sits x meters from the...
Homework Statement
A child weighs 34 Kg is seated on a seesaw. While a child who weighs 40 kg is situated on tghe opposite end of the seesaw. The functio B(x)= 34x / 40 gives the distance that the 40 kg child must sit from the center of the seesaw when the 34 kg child sits x meters from the...
A 70kg adult sits at one end of a 10m board, on other end sits a 30kg child. where should pivot point be placed so board is balanced? board's mass is 15kg.
so far, i have pivot point is 15kg(9.8)=147N (5) <-- half the board length.. for adult i have 686N and kid is 294N. i know that...
Seesaw: simple statics problem?
Q:
A uniform seesaw is of length 3.90 m and weighs 235 N. The seesaw is pivoted about a point on its bottom surface and the location of this pivot along the length of the seesaw can be adjusted as far as a distance 0.170 m from the center of the seesaw. Little...
Problem: I have to find out the power that is required to set the balanced seesaw from equilibrium to an oscillation that changes direction in an inclination of 30°.
I also have to know the power required to eventually stop that motion and bring the seesaw back to equilibrium.
I have...
At first glance the physics of a seesaw seem quite simple, however I've been stumped on a problem. For part of my Physics project, I am incorporating a seesaw catapult where one weight will be dropped on one side launching the hacky sack on the other side. Simple right? Of course... but the...
My main goal was the find the angular acceleration of the seesaw.
The swing bar of mass is pivoted at a different point, as shown in the figure.
Find the magnitude of the angular acceleration of the swing bar. Be sure to use the absolute value function in your answer, since no comparison...