- #1

Tepictoc

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## Homework Statement

It's a balanced seesaw but the pivot isn't in the exact middle and two weights are on it. One at the very end of each side.

The weight on the left is 4.8 kg.[m1]

The weight on the right is 5.5 kg[m2]

The length of the entire seesaw is 5m

L1 is the distance from the pivot on the left side to the end of the board where m1 is.

Calculate the distance L1 from the pivot when the board is balanced.

## Homework Equations

Distance = Torque/force

Sum of all moments = 0

## The Attempt at a Solution

m1*g=47.088 N This force is acting counterclockwise

m2*g=53.955 N This force is acting clockwise

The normal force from the pivot is m1g+m2g = 101,043 N

I'll use L2 to identify the length from the pivot to the right end since L1 is the length from pivot to the left end.

53.955*L2 = 47.088*L1

This is where I get stuck when trying to calculate the lengths of L1 and L2.

I could calculate the length of L1 and L2 if I knew the torque by dividing it by the force but it's unknown isn't it?