Center of Gravity/ Seesaw problem?

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SUMMARY

The discussion revolves around solving the Center of Gravity (CG) problem for a wooden beam weighing 820 N and measuring 3.2 m in length, with its CG located 1.4 m from one end. The two workers lifting the beam at its ends must balance the forces they exert, denoted as x and y. The key equations involved are Tcw = Tccw and F*l = F*l, which relate the torques and forces acting on the beam. To solve for the forces, it is essential to establish that the sum of the forces x and y equals the total weight of the beam, 820 N.

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laneybaney
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Homework Statement


A large wooden beam weighs 820 N and is 3.2 m long. the beam's CG is 1.4 m from one end. two workers carry it away. If they lift the beam at its ends, what part of the weight does each worker lift?


Homework Equations



Tcw=Tccw
F*l=F*l

The Attempt at a Solution


I tried drawing out the picture and doing

1.4(x)= 1.8(y)
I realize you can't have two variables so I'm very confused

Any help is apreciated!
 
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laneybaney said:

Homework Statement


A large wooden beam weighs 820 N and is 3.2 m long. the beam's CG is 1.4 m from one end. two workers carry it away. If they lift the beam at its ends, what part of the weight does each worker lift?

Homework Equations



Tcw=Tccw
F*l=F*l

The Attempt at a Solution


I tried drawing out the picture and doing

1.4(x)= 1.8(y)
I realize you can't have two variables so I'm very confused

Any help is appreciated!
Hello laneybaney. Welcome to PF !

From what you set up, I take it that one worked lifts with a force, x, and the other lifts with a force of y .

There's one more equation you need so that you can solve two equations in two unknowns.

What must the sum x+y be equal to ?
 

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