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Center of Gravity/ Seesaw problem?

  1. Jan 31, 2013 #1
    1. The problem statement, all variables and given/known data
    A large wooden beam weighs 820 N and is 3.2 m long. the beam's CG is 1.4 m from one end. two workers carry it away. If they lift the beam at its ends, what part of the weight does each worker lift?


    2. Relevant equations

    Tcw=Tccw
    F*l=F*l

    3. The attempt at a solution
    I tried drawing out the picture and doing

    1.4(x)= 1.8(y)
    I realize you can't have two variables so I'm very confused

    Any help is apreciated!
     
  2. jcsd
  3. Jan 31, 2013 #2

    SammyS

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    Hello laneybaney. Welcome to PF !

    From what you set up, I take it that one worked lifts with a force, x, and the other lifts with a force of y .

    There's one more equation you need so that you can solve two equations in two unknowns.

    What must the sum x+y be equal to ?
     
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