Prove that A4 has no subgroup of order 6 in this way (and this way only):
Suppose that A4 has a subgroup H of order 6. Explain (in one sentence) why H must contain a 3-cycle. WLOG(without loss of generality) let this be (1,2,3).
Then H must have iota,(1,2,3) and (1,2,3)^-1=(3,2,1).
Now...