0-60mph back down to 0 = X feet

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SUMMARY

The discussion focuses on calculating the total distance traveled when accelerating from 0 to 60 mph and then decelerating back to 0 mph. Given the acceleration time of 6.7 seconds and a braking distance of 112 feet, the total distance can be approximated using the area under the speed-time graph. Assuming constant acceleration, the distance covered during acceleration is calculated as 295 feet, resulting in a total distance of 407 feet (295 feet + 112 feet).

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinematics.
  • Familiarity with speed-time graphs and area calculations.
  • Knowledge of acceleration and deceleration principles.
  • Basic mathematical skills for calculating areas of triangles.
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  • Research kinematic equations for uniform acceleration.
  • Learn about the physics of braking distances and factors affecting them.
  • Explore speed-time graph analysis techniques.
  • Study real-world applications of acceleration and deceleration in automotive engineering.
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This discussion is beneficial for automotive engineers, physics students, and individuals preparing for traffic court cases related to speed and braking distances.

sapple
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0-60-0 Help :(

I am going to court tomorrow for a trafic citation and need to figure out the following

0-60mph back down to 0 = X feet


information i have:

0-60 = 6.7 sec

60-0 = 112 feet
 
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It seems your braking (or was it a collision?) was much more effective than the acceleration. It is only possible to give an approximation answer in this case since your speed most likely did not change uniformly as you accelerated. If one assumes that it did change at a constant rate then the total distance traveled while going from 0 - 60 (0 - 88 ft/sec) is just the area under the speed time graph which will then be the area of a triangle with a base of 6.7 sec and a height of 88 feet/sec which gives a distance of 295 feet.
 

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