0 Electric potential between point charges?

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SUMMARY

The discussion clarifies the concept of zero electric potential between opposite charges, specifically addressing the conditions under which this occurs. It explains that while the electric potential due to a positive charge is expressed as V_1=kq/r_1 and for a negative charge as V_2=kq/r_2, their combination can yield a point in space where the total potential is zero. This occurs when the net work done on a test charge moving from infinity to this point is zero, despite the presence of electric fields. The relationship E = -grad(V) is emphasized, indicating that while potential can be zero, the electric field gradient can still be finite.

PREREQUISITES
  • Understanding of electric potential and its mathematical representation (V=kq/r)
  • Familiarity with the concept of electric fields and forces on charges
  • Knowledge of vector calculus, particularly gradients
  • Basic principles of electrostatics and charge interactions
NEXT STEPS
  • Explore the concept of electric field lines and their relationship to electric potential
  • Study the mathematical derivation of electric potential from point charges
  • Learn about the superposition principle in electrostatics
  • Investigate the implications of zero electric potential in different charge configurations
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Students of physics, electrical engineers, and anyone interested in understanding electrostatics and electric potential theory.

blazen2392
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Can someone explain how you can have a zero electric potential between opposite charges?
a charge would move there. I thought electric potential was the measure of energy per charge. wouldn't a 0 electric potential imply that a test charge cannot have any potential energy at this point? how is this possible if it is moving.
 
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The electric potential due to a positive point charge is V_1=kq/r_1 where r_1 is the distance to the opposite charge. It's value will be positive due the charge being positive.

The electric potential due to a negative point charge is V_2=kq/r_2 where r_2 is the distance to the opposite charge. It's value will be negative due the charge being negative.

The potential (or potential difference) would be V_1-V_2 or V_2-V_1. Since they are oppositely charged these expressions will linearly combine, either producing positive potential difference or a negative potential difference, but not zero.

However, you can have a point in 3-space that the potential is zero due to their combination. For example,

V=kq_1/r_1+kq_2/r_2

Set V=0, and you should be able to find a point where the potential is zero.
 
If you had two equal and opposite charges and moved a test charge on a line from infinity perpendicularly to the mid-point between the two charges, the net force on the test charge would always be zero, so no work would be done by or on the test charge and its potential would by definition then be zero.

Even if the charges were not equal and opposite, as long as they were of opposite polarity you could find a path from infinity to some point between them such that the net work done is zero. (I think!).
 
rude man said:
If you had two equal and opposite charges and moved a test charge on a line from infinity perpendicularly to the mid-point between the two charges, the net force on the test charge would always be zero, so no work would be done by or on the test charge and its potential would by definition then be zero.

Even if the charges were not equal and opposite, as long as they were of opposite polarity you could find a path from infinity to some point between them such that the net work done is zero. (I think!).

So if you knew that the electric potential at some point in space was 0, what excatly does this tell you? it would obviously move at this point right?
 
blazen2392 said:
So if you knew that the electric potential at some point in space was 0, what excatly does this tell you? it would obviously move at this point right?

Yes, butthe force on the test charge would be perpendicular to the line of travel, all the way from infinity to its final position between the two opposite-polarity charges. What would be the work done?

E = - grad(V). V can be zero but grad(V) finite! You can show this by moving the test charge a small amount dx towards one of the charges, recomputing V, then taking dV/dx.
 

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