0 Electric potential between point charges?

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Homework Help Overview

The discussion revolves around the concept of electric potential in the context of point charges, specifically addressing the conditions under which the electric potential can be zero between opposite charges. Participants explore the implications of zero electric potential and the behavior of test charges in this scenario.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants question how zero electric potential can exist between opposite charges and what it implies for a test charge. They discuss the mathematical expressions for electric potential due to positive and negative charges and consider the conditions under which the net potential can be zero. Some participants explore the idea of moving a test charge and the work done in relation to electric potential.

Discussion Status

The discussion is active, with participants offering various interpretations of electric potential and its implications. There are multiple lines of reasoning being explored, particularly regarding the relationship between electric potential, force, and work done on a test charge. No consensus has been reached yet.

Contextual Notes

Some participants express uncertainty about the definitions and implications of electric potential, particularly in relation to the movement of test charges and the work done in electric fields. The discussion includes considerations of both equal and unequal opposite charges.

blazen2392
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Can someone explain how you can have a zero electric potential between opposite charges?
a charge would move there. I thought electric potential was the measure of energy per charge. wouldn't a 0 electric potential imply that a test charge cannot have any potential energy at this point? how is this possible if it is moving.
 
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The electric potential due to a positive point charge is [itex]V_1=kq/r_1[/itex] where [itex]r_1[/itex] is the distance to the opposite charge. It's value will be positive due the charge being positive.

The electric potential due to a negative point charge is [itex]V_2=kq/r_2[/itex] where [itex]r_2[/itex] is the distance to the opposite charge. It's value will be negative due the charge being negative.

The potential (or potential difference) would be [itex]V_1-V_2[/itex] or [itex]V_2-V_1[/itex]. Since they are oppositely charged these expressions will linearly combine, either producing positive potential difference or a negative potential difference, but not zero.

However, you can have a point in 3-space that the potential is zero due to their combination. For example,

[tex]V=kq_1/r_1+kq_2/r_2[/tex]

Set V=0, and you should be able to find a point where the potential is zero.
 
If you had two equal and opposite charges and moved a test charge on a line from infinity perpendicularly to the mid-point between the two charges, the net force on the test charge would always be zero, so no work would be done by or on the test charge and its potential would by definition then be zero.

Even if the charges were not equal and opposite, as long as they were of opposite polarity you could find a path from infinity to some point between them such that the net work done is zero. (I think!).
 
rude man said:
If you had two equal and opposite charges and moved a test charge on a line from infinity perpendicularly to the mid-point between the two charges, the net force on the test charge would always be zero, so no work would be done by or on the test charge and its potential would by definition then be zero.

Even if the charges were not equal and opposite, as long as they were of opposite polarity you could find a path from infinity to some point between them such that the net work done is zero. (I think!).

So if you knew that the electric potential at some point in space was 0, what excatly does this tell you? it would obviously move at this point right?
 
blazen2392 said:
So if you knew that the electric potential at some point in space was 0, what excatly does this tell you? it would obviously move at this point right?

Yes, butthe force on the test charge would be perpendicular to the line of travel, all the way from infinity to its final position between the two opposite-polarity charges. What would be the work done?

E = - grad(V). V can be zero but grad(V) finite! You can show this by moving the test charge a small amount dx towards one of the charges, recomputing V, then taking dV/dx.
 

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