1 dimensional kinematics with car and motorcycle

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SUMMARY

The discussion focuses on a physics problem involving 1D kinematics with two friends, Steve and Jack, testing their understanding of motion. Jack travels at a constant velocity v0, while Steve accelerates from rest. Key conclusions include that Steve's velocity upon meeting Jack is derived from the equation v = v0, and his acceleration is correctly expressed as a = v^2/2d. Additionally, the time of their meeting is calculated as tF = 2d/v0, and the distance Jack travels is confirmed to be xF = 2d.

PREREQUISITES
  • Understanding of 1D kinematics principles
  • Familiarity with equations of motion for uniformly accelerated objects
  • Knowledge of constant velocity concepts
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the equations of motion for uniformly accelerated motion
  • Learn about relative motion in physics
  • Explore the concept of instantaneous velocity
  • Investigate graphical representations of motion, such as position-time graphs
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for examples of 1D motion problems.

tk24700
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Homework Statement


Two friends agree to test their physics background in 1D motion. Steve, is a distance d ahead of Jack. Jack is driving at a constant, know velocity v0 when they start their experiment. At this moment, Steve accelerates from rest with his motorcycle in such a way that they only meet once at time tF at a distance xF from where Jack started the experiment.
a)What is the velocity of Steve starting from rest once he meets Jack in terms of v0
b) show that the acceleration for Steve is given by a= v^2/2a
c) Show that the time tF is given by : tF= 2d/v0
d) Show that the distance xF, i.e. the distance Jack traveled after he started counting the experiment, is given by: xF= 2d

Homework Equations

The Attempt at a Solution


I have b and c. I cannot for my life seem to get (a and d). Any hints or help would help. [/B]
 
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tk24700 said:
Jack is driving at a constant, know velocity v0 when they start their experiment.
v_0 in which direction? Towards Steve or away from him?
Also, does Steve undergo uniform acceleration?
 
For (a) you can make a logical argument about what Steve's speed must be when they meet given that they do meet and only once.

For (d), consider your answer to (c) and what you know about Jack's speed.
 
tk24700 said:
b) show that the acceleration for Steve is given by a= v^2/2a
Is there a typo here?
 
insightful said:
Is there a typo here?
Yes, it should be a= v^2/2d
 

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