Two friends agree to test their physics background in 1D motion. Steve, is a distance d ahead of Jack. Jack is driving at a constant, know velocity v0 when they start their experiment. At this moment, Steve accelerates from rest with his motorcycle in such a way that they only meet once at time tF at a distance xF from where Jack started the experiment.
a)What is the velocity of Steve starting from rest once he meets Jack in terms of v0
b) show that the acceleration for Steve is given by a= v^2/2a
c) Show that the time tF is given by : tF= 2d/v0
d) Show that the distance xF, i.e. the distance Jack traveled after he started counting the experiment, is given by: xF= 2d
The Attempt at a Solution
I have b and c. I cannot for my life seem to get (a and d). Any hints or help would help. [/B]