# 100sin(alpha) = 500cos(alpha) - how do you solve such a thing?

Gold Member
100sin(alpha) = 500cos(alpha) ---- how do you solve such a thing?

100sin(alpha) = 500cos(alpha)

I see there's only one unknown, but I'm a little befuddled how to approach trigo equations like that when the angle is unkown (I know about the arc-cos/sin/tan function) but there are 2 functions in the equation! Cosine AND Sine! Arg...... perhaps you guys can help me with a short guide/link/whatever...

I'll appreciate the help :)

-Dory

Why don't you square both sides. Do you know of any relation relating squares of sines and cosines?

Mentallic
Homework Helper

Or even more simply, divide through by $$\cos(\alpha)$$

Gold Member

Thanks! Right, I forgot that sine/cosine is tan! :) That simplifies things!

Or even more simply, divide through by $$\cos(\alpha)$$

Oh!! :P