15.2.78 But it asks for a double integral

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SUMMARY

The discussion focuses on calculating the area of the region bounded by the curves \(y=4+4\sin{x}\) and \(y=4-4\sin{x}\) using a double integral. The specific double integral formulation provided is \(\int_0^\pi\int_{4-4\sin x}^{4+4\sin x}dy\,dx\). While the computation can be simplified to a single integral, the requirement to use a double integral is emphasized as a formal necessity in this context.

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karush
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Use double integral to compute the area of the region
bounded by $y=4+4\sin{x}$ and $y=4-4\sin{x}$
on the interval $\left[0,\pi\right]$

View attachment 7253

ok it looks easier to do this in one $\int$ but it asks for a double $\int\int$ so ?
 

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Re: 15.2.78 but it asks for a double integral

karush said:
Use double integral to compute the area of the region
bounded by $y=4+4\sin{x}$ and $y=4-4\sin{x}$
on the interval $\left[0,\pi\right]$
ok it looks easier to do this in one $\int$ but it asks for a double $\int\int$ so ?
$$\int_0^\pi\int_{4-4\sin x}^{4+4\sin x}dy\,dx$$ Okay, it's just a single integral in disguise, but formally it's a double integral.
 

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