1st order Pertubation energy and wavefunction

  • Thread starter luxiaolei
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  • #1
luxiaolei
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Hi all,

I must misunderstood somewhere, couldn't figure out the following, any helps will be greatly appreciated.

The first order correction of the pertubated energy is:

[itex]\leftψn0\langle[/itex] H'[itex]\rightψn0\rangle[/itex]

Where:
ψn0
Is the solution of the unpertubated Hamiltonian.

My question is can ψn0 be the general solution to the Hamiltonian or has to be a specified state vector?

i.e.,

ψn0= aψ10+bψ20

Or has to be:

ψn010

If it can be the superposition of the eigenstates, then how to construct the first order wave function?
Thanks in advance:)
 

Answers and Replies

  • #2
dextercioby
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The correction is calculated for a particular eigenvector of the Hamiltonian and not for a superposition of several eigenvectors.
 
  • #3
luxiaolei
75
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The correction is calculated for a particular eigenvector of the Hamiltonian and not for a superposition of several eigenvectors.

Thank you so much!
 

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