MHB 2.4.3 AP Calculus Exam Integration limits

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The discussion focuses on the properties of definite integrals, specifically the relationship between integrals with varying limits. It highlights that the integral from \(b\) to \(x\) can be expressed as the negative of the integral from \(x\) to \(b\), leading to the conclusion that their sum equals zero. The participants clarify that the integrands must indeed be functions of \(x\) for the properties to hold. Additionally, it emphasizes the importance of understanding how to manipulate limits in integrals to derive correct results. The conversation underscores the foundational concepts necessary for solving AP Calculus exam problems related to integration limits.
karush
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by observation I choose (c) since the limit values may not be =
 
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Are you sure the integrands are supposed to be functions of \(x\)?
 
hint ...

$\displaystyle \int_b^x g(t) \, dt = -\int_x^b g(t) \, dt$
 
so then
$\displaystyle \int_b^x g(t) \, dt +\int_x^b g(t) \, dt=0$
 
that’s not the problem
 
$\displaystyle \int_a^x g(t) \, dt - \int_b^x g(t) \, dt = \int_a^x g(t) \, dt + \int_x^b g(t) \, dt = \int_a^b g(t) \, dt$
 
Properties of definite integrals ...

0*Ywl_mQYeUvSIjymd.png
 

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