2.6.62 inverse integrals with substitution

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Discussion Overview

The discussion revolves around the application of inverse integrals with substitution, focusing on a specific problem from an Overleaf document. Participants seek clarification on the use of variables and the correctness of their mathematical expressions.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant expresses uncertainty about the use of variables b, x, and u in their solution, indicating a need for comments on their work.
  • Another participant requests clarification on the specific question being posed.
  • A participant acknowledges the potential for errors in substitution, particularly in relation to a specific problem.
  • A later reply identifies a correction regarding the differential notation, noting that $du=dx$ should actually be $\dfrac{du}{4} = dx$, while acknowledging that the subsequent line uses the correct form.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the initial solution, as there are indications of uncertainty and a correction provided, suggesting that multiple views on the solution's accuracy exist.

Contextual Notes

There are limitations in the clarity of the question being asked and the specific details of the solution provided, which may affect the discussion.

karush
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View attachment 9266
ok this is from my overleaf doc
so too many custorm macros to just paste in code
but I think its ok,,, not sure about all details.
appreciate comments...

I got ? somewhat on b and x and u being used in the right places
 

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Last edited:
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karush said:
ok this is from my overleaf doc
so too many custorm macros to just paste in code
but I think its ok,,, not sure about all details.
appreciate comments...

I got ? somewhat on b and x and u being used in the right places
Ummm...

What exactly is your question?

-Dan
 
OK this one was kinda obvious but usually that is where I make the errors especially where there is substitution.
I post another one here soon.:cool:
 
karush said:
View attachment 9267
That all looks correct to me, except that at one point in the solution of 6.6.62 you have written $du=dx$. That should be $\dfrac{du}4 = dx$ (which is what you have correctly used in the following line).
 

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