Unfortunately this is due today, I will go work on another problem and watch these boards. And its not a last minute thing, I have been working on this since it was assigned... 1. The problem statement, all variables and given/known data The lower block in Figure P8.28 is pulled on by a rope with a tension force of F = 28 N. The coefficient of kinetic friction between the lower block and the surface is 0.34. The coefficient of kinetic friction between the lower block and the upper block is also 0.34. What is the acceleration of the 2.0 kg block? http://img27.imageshack.us/img27/6212/abaabab.gif [Broken] 2. Relevant equations F=ma fk=μkn 3. The attempt at a solution I drew out my free-body diagrams. Here are the formulas I gained from them (if they were right). m1 (Top Mass) Fx1=fk2 on 1-T2 on 1 Fy1=n1-m1g m2 (Bottom Mass) Fx2=F-T1 on 2-fk1 on 2-fk2 Fy2=n2-mg-n1 on 2 etc etc etc... Question is, after I have formulas T2 on 1=μk(m2g+m1g) T1 on 2=F-μkm1g-μk(m2g+m1g) T2 on 1 is coming out to be 9.996N while T1 on 2 is coming out 14.672N Am I missing something? They are connected so would the tensions not be the same? I am thinking I have a concept mixed up or are they not supposed to be the same? Anyway I ask because I tried to use formula Fx2=m2ax2 and it gave me the wrong acceleration, so I am curious if anyone can see my problem?