2 Charged thick plates placed next to each other.

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Homework Statement



Two thick, parallel plates of thickness d and uniform charge densities
(Coulombs per unit volume) ρ and −ρ are placed next to each other, as
shown in the figure. The negatively charged plate is located between –d
and 0 on the x-axis and the positively charged plate between 0 and d on
the x-axis. The z-axis points out of the page. Assume that both plates
are infinite in y and z. Find the expressions for the x-, y-, and zcomponents
of the electric field E(x) as a function of the x-coordinate.
Write your solution in terms of ε0, not ke.
Is the net force per unit area between the plates: attractive, repulsive or zero.
Setup the integral to compute the pressure on the plates


Homework Equations



I believe Gauss Law could be used: Flux = Qin/ε.

The Attempt at a Solution


I would imagine a cylinder crossing the 2 plates and measure the field on each surface: they are going to be in the same direction, I think. The problem is that I cannot fully imagine the situation: Is the field w on the left and equal to the sum on the right?
 
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I don't think that would work as we are not looking at the interaction between the two plates but rather the superposition of the two fields: Here is the image:
http://img163.imageshack.us/img163/5497/phys.jpg
Any guesses?
 
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I'm suggesting that you can divide each think plate into a stack of parallel thin plates. The field at some point within a thick plate then translates to the field between thin plates (with different total charges each side). As for the field beyond the thick plates.. you know what that will be, yes?
 
Will that be a ZERO?
I mean, the question asks for the field everywhere: that excludes the plate, right?
SO they are asking about the field outside of it! = ZERO?
 
Ok, so I tried this problem and I found that inside the sheets, E = Rho*x/ε.
Would that be correct?
 
Ghastn said:
Ok, so I tried this problem and I found that inside the sheets, E = Rho*x/ε.
Would that be correct?
No. That does not approach zero as x → d .

How did you arrive at that answer.

You know that E = 0 for x < -d and E = 0 for x > d .

Start at x = -d and use Gauss's Law to find E for -d ≤ x ≤ 0 .