Two identical circuits are cascaded, without the second circuit having any loading effect on the first circuit. If the laplace transform of the impulse response of the cascade is 4/(s+1)^2. a)determine the impulse response of each circuit alone as a function of time.
b)if a signal u(t) is applied to the input of the first circuit, determine the output of the second circuit as a function of time
The Attempt at a Solution
a) the impulse response of each circuit is either H(s)=+-(2/s+1) so h(t)=+-2e^-t
b)the laplace transform of the output is (4/(s*(s+1)^2) then do partial fractions and u can easily make inverse laplace and get the answer
These are the soulutions to the problem, however I don't get them. What do they mean by the second circuit does not have any loading effect on the first? And why did they multiply laplace of u(t) with laplace of the cascade to get the laplace of the input? I'm not really understanding the concepts.