2 more thermal expansion questions

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Homework Help Overview

The discussion revolves around two thermal expansion questions involving a steel rod and a brass ring, as well as the effect of temperature on a grandfather clock's pendulum. The subject area includes thermal expansion concepts and their implications on physical dimensions and timekeeping.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate equations for thermal expansion, questioning whether to use volume change or linear expansion formulas. There are attempts to relate temperature changes to diameter adjustments for the rod and ring. For the pendulum, questions arise about how temperature affects its period and length.

Discussion Status

Some participants suggest using the linear expansion equation instead of the volume change equation for the first question. Hints have been provided regarding the relationship between the pendulum's period and its length, although some participants express uncertainty about how to apply this information.

Contextual Notes

Participants are navigating through the application of thermal expansion principles, with some uncertainty about the specific relationships involved in the problems. The original poster expresses a lack of clarity on how to approach the questions, indicating a need for foundational understanding.

F|234K
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1.) a steel rod is 3 cm in diameter at 25 C. a brass ring has an interior diameter of 2.992 cm at 25 C. at what common temperture will the ring just slide into the rod?

for this Q, i am not too sure which equation to use. i think it's the volume change one, which is delta V= beta(Vo)(delta T)

but i don't know how the temperature and the diameter is going to fit in...

2.) a grandfather's clock is calibrated at a temperature of 20 C. the pendulum is a think brass rod with a heavy mass attached to the end. on a hot day, when the temperature is 30 C, does the clock run fast or slow? how much time does it gain or lose in a 24 hour period?

this Q...i just have no idea how to start...

thanks in advance, any suggestions/comments are greatly appreciated.
 
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F|234K said:
1.) a steel rod is 3 cm in diameter at 25 C. a brass ring has an interior diameter of 2.992 cm at 25 C. at what common temperture will the ring just slide into the rod?

for this Q, i am not too sure which equation to use. i think it's the volume change one, which is delta V= beta(Vo)(delta T)

but i don't know how the temperature and the diameter is going to fit in...
Forget about volume; the rod will just slide into the ring when their diameters are the same. You need to find the \Delta T that will have them end up with the same diameter.
2.) a grandfather's clock is calibrated at a temperature of 20 C. the pendulum is a think brass rod with a heavy mass attached to the end. on a hot day, when the temperature is 30 C, does the clock run fast or slow? how much time does it gain or lose in a 24 hour period?
Hint: How does the period of a pendulum depend on its length?
 
for number one, are u suggesting taht i should use the linear equation instead of the volume one?

linear equation being delta L=alpha(Lo)(delta T)
 
Last edited:
"Hint: How does the period of a pendulum depend on its length?"

taht the thing i don't no...so i can't do the Q...
 
F|234K said:
for number one, are u suggesting taht i should use the linear equation instead of the volume one?
Absolutely.

Regarding the pendulum: Look it up! :smile:
 
thanks a lot.
 

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