Need help on Thermodynamics problem: thermal expansion to be more specific

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Homework Help Overview

The discussion revolves around a thermodynamics problem involving thermal expansion, specifically focusing on a steel ring and a brass shaft with given dimensions and temperatures. The original poster seeks assistance in determining the necessary temperature for the ring to fit over the shaft and the temperature at which the ring will slip off the shaft when cooled.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the thermal expansion formula, converting diameters to meters and using a specific coefficient of thermal expansion. Some participants question the arithmetic and suggest verifying calculations, while others request to see the detailed calculations to identify potential errors.

Discussion Status

The discussion is ongoing, with participants actively engaging in checking calculations and providing feedback on the original poster's approach. There is no explicit consensus on the correct answer yet, as participants are still exploring the arithmetic and assumptions involved.

Contextual Notes

Participants note that there may be unnecessary unit conversions in the original poster's calculations, which could affect the results. The specific coefficients and values used are also under scrutiny.

Juniorphysics
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Need help on Thermodynamics problem: thermal expansion to be more specific!

A steel ring with a 2.5000in- inside diameter at 20.0°C is to be warmed and slipped over a brass shaft with a 2.5015in outside diameter at 20.0°C.
Part A:

To what temperature should the ring be warmed?

Part B:

If the ring and the shaft together are cooled by some means such as liquid air, at what temperature will the ring just slip off the shaft?

Attempt at solution:
using dL=alphaLidT
i converted the diameters to meters because i was given alpha in m/m°C. so i got d1=0.0635m d2=0.0635381m and dL=0.0000381m
i used alpha=13*10-7m/m°C
and got dT to be 45.9 but that gave me the incorrect answer
 
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Juniorphysics said:
and got dT to be 45.9 but that gave me the incorrect answer
Double check your arithmetic. (FYI: No need to change units for the lengths.)
 


It gave me the same answer
 


Show your calculation. You are off by about a factor of 10.
 

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