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Thermal coefficients of expansion

  1. Oct 22, 2015 #1
    1. The problem statement, all variables and given/known data
    A brass rod (linear expansion coef 19*10-6/°C) has a radius of 8139 cm and a copper (linear expansion coef 17*10-6/°C) sheet has a hole or radius 8139+8.86cm. What temperature change (K) is required to close the gap?

    2. Relevant equations
    ΔL/Lo = αΔT?

    3. The attempt at a solution
    I'm not even sure if the equation is right, so I'm really confused. Thanks for the help!
     
  2. jcsd
  3. Oct 22, 2015 #2

    SteamKing

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    That's some rod, if it has a diameter of over 16 meters!

    Are you certain these are the dimensions for this problem?
     
  4. Oct 22, 2015 #3
    I'm positive!
     
  5. Oct 23, 2015 #4
    The equation is not correct. It should be:
    $$L=L_0(1+\alpha \Delta T)$$So, if the temperature rises ΔT, in terms of #\Delta T#, what it the new radius of the rod? What is the new radius of the hole in the sheet?
     
  6. Oct 26, 2015 #5
    I'm not entirely sure. I don't really understand the formula, so I'm having a hard time really wrapping my mind around it. I don't know what the L represents.
     
  7. Oct 26, 2015 #6
    Please say in words your understanding of the concept of thermal expansion.

    Chet
     
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