2 parallel rays are travelling in a medium

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Homework Help Overview

The problem involves two parallel rays traveling through different media, specifically one ray passing through a glass slab while the other travels through a medium with a different refractive index. The objective is to determine the path difference between the two rays due to the presence of the glass slab.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of optical paths for both rays, questioning the assumptions made regarding the refractive indices and the medium through which each ray travels. There are attempts to clarify the relationship between the refractive indices and the resulting path difference.

Discussion Status

The discussion is active, with participants providing different interpretations of the problem and exploring various approaches to calculate the path difference. Some guidance has been offered regarding the calculation methods, but there is no explicit consensus on the correct answer yet.

Contextual Notes

There are indications of confusion regarding the refractive indices and the media involved, particularly the assumption of the surrounding medium's refractive index. Participants are also considering the implications of these assumptions on the final calculations.

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Homework Statement


2 parallel rays are traveling in a medium of refractive index 4/3. One of the rays passes through a parallel glass slab of thickness t and refractive index 3/2. What will be the path differnce between the two rays due to the glass slab?


The Attempt at a Solution



The optical path covered by the ray inside the glass slab equals the phase difference.
So x=3/2 x t

The answer is incorrect.
 
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Dear AbdulKadir, that is easy;
l=nx right?
for first one l=(4/3)t
for second one l'=(3/2)t
path difference is (1/6)t, don't get confused, other is not traveling at space it also in a medium
 


Phase difference would be the difference in optical paths. One ray goes through a medium of r index 3/2, other through 4/3. Find the optical paths and subtract.
 


sigmaro said:
AbdulKadir

:rolleyes:

sigmaro said:
l=nx right?
for first one l=(4/3)t
for second one l'=(3/2)t
path difference is (1/6)t, don't get confused, other is not traveling at space it also in a medium

The first ray doesnot travel through the glass slab. How did you write 4/3t?

Sourabh N said:
Phase difference would be the difference in optical paths. One ray goes through a medium of r index 3/2, other through 4/3. Find the optical paths and subtract.

So do you mean the answer will be (1/6)t?
 


Yes.
 


Sorry that answer is incorrect.
 


A trivial problem - We have assumed c = 1. Does the answer assume that too?

A not so trivial problem - The refractive index of glass slab wrt the surrounding medium is (3/2) / (4/3) = 9/8. So the path difference would be 9/8 * t - t = 1/8 * t. This makes more sense to me because the background medium is not air (with r index 1), but a medium with r index 4/3. Does it make sense to you?
 


You are correct now.
But I didnot understand one thing, why did you subtract t from 9/8*t ?
 


9/8 * t is the optical path through the glass slab (placed in water), t is the optical path in water. Path difference = Subtract them.

In other words, the same reason we subtracted 4/3 * t earlier.
 
  • #10


Thanks!
 

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