2 parallel rods carrying the same current

  • Thread starter Thread starter Dart82
  • Start date Start date
  • Tags Tags
    Current Parallel
Click For Summary
SUMMARY

The discussion revolves around calculating the current in two parallel rods carrying the same current, positioned 0.70 m long and 8.2 x 10-3 m apart. The relevant equations include the magnetic force equation F = ILBsin(theta) and the magnetic field equation B = (μI)/(2πr). The participants conclude that since the rods are in equilibrium, the magnetic force between them equals the gravitational force acting on the rods, allowing for the establishment of a system of equations to solve for both current (I) and magnetic field (B).

PREREQUISITES
  • Understanding of magnetic forces and fields
  • Familiarity with the equations F = ILBsin(theta) and B = (μI)/(2πr)
  • Basic algebra skills for solving systems of equations
  • Knowledge of gravitational force calculations
NEXT STEPS
  • Study the derivation and application of the equation F = ILBsin(theta)
  • Learn about the properties of magnetic fields generated by current-carrying conductors
  • Explore methods for solving systems of equations, particularly substitution and elimination
  • Investigate the concept of magnetic force equilibrium in physics
USEFUL FOR

Physics students, educators, and anyone interested in electromagnetism and the behavior of current-carrying conductors in magnetic fields.

Dart82
Messages
56
Reaction score
0

Homework Statement


Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The length of each rod is 0.70 m, while the mass of each is 0.071 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 8.2 10-3 m. Determine the current in the rods.

[URL=http://img53.imageshack.us/my.php?image=problem3ta5.gif][PLAIN]http://img53.imageshack.us/img53/5664/problem3ta5.th.gif[/URL][/PLAIN]



Homework Equations


F = ILBsin(theta)
B = (uI)/(2 pi r)



The Attempt at a Solution


i know that current will be the same for both rods and since the current is flowing in the same direction, the magnetic force will be attractive between the rods. i know the length of each wire and the mass. i don't know how to progress in this problem because it seems to me that i need to know the magnetic field to be able to solve either equation. is there a way to solve this problem without knowing the magnetic field or am i overlooking something here? I'm stumped.
 
Physics news on Phys.org
Well you can have two equations with two unknowns, and it is possible to find both unknowns. Its kind of like solving for x and y with two algebraic equations. Only difference is that here, we have current and the magnetic field.
 
i'm sorry but is there possibly another way to say what you just told me; i don't get it. Am i even using the correct formulas? if i try to use F = ILB sin(theta) and solve for I, i get stuck because i don't know how to find B. If i try to solve B=(uI)/(2 pi r) i run into the same situation.. i don't know I or B. I know this problem cannot be as hard as it seems to me...
 
Okay so since the rods are not falling towards the Earth or each other, that must mean that the force between the rods is equal to that of gravity. So we have:
mg = ILB sin(theta)
B = (uI)/(2 pi r)

We know all the values for all variables there, except B and I. Now using a system of equations, can you solve for both B and I? You can use the method of substitution or elimination, whatever makes you happy.
 
Last edited:
ok, i'll give it another shot. thank you.
 

Similar threads

Replies
2
Views
1K
Replies
7
Views
1K
Replies
11
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K