2 Part Kinematic Equation Problem

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SUMMARY

The discussion centers on a kinematic equation problem involving a police car chasing a car traveling at a constant speed of 75 ft/s. To catch up in 12 seconds, the police car must accelerate at a rate of 12.50 ft/s². After 12 seconds of acceleration, the police car's final speed will reach 150 ft/s. The calculations utilize fundamental kinematic equations, confirming the accuracy of the approach taken by the participants.

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Homework Statement


A car driving at a constant speed of 75 ft/s passes a police car that is initially at rest. If the police car decides to give chase
A) What rate would the police have to accelerate to catch up with the other car in 12 seconds?
B) What is the police car's speed at the end of the 12 seconds?


Homework Equations


Use Kinematic Equations


The Attempt at a Solution


The first car's displacement would be 75 ft/s * 12 seconds = 900 feet? So if I use X = volt + 1/2(at^2)that means that acceleration of the second car would have to be 12.50 ft/s Is this the correct? Or am I way off? So if the acceleration = 12.50 ft/s I use V = Vo + at and end up with Final V = 150 ft/s ? That just doesn't sound right to me, could you please try to explain what I'm doing wrong?
 
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