2 Port analysis of series Inductor (Simple)

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SUMMARY

The discussion focuses on calculating the S-parameters for a 2-port network consisting of a series inductor with an impedance of Z = j 100 Ω in a 50 Ω system. The user successfully derived S22 as S22 = 1/2(1 + j) and expressed confusion regarding the negative value of S12, which they calculated as S12 = -1. The discussion clarifies that a negative transmission coefficient indicates a phase shift of π, confirming the user's calculations are correct. The conversation also suggests alternative methods for obtaining S-parameters using Y-parameters.

PREREQUISITES
  • Understanding of S-parameters and their significance in network analysis.
  • Familiarity with impedance concepts, specifically in 50 Ω systems.
  • Knowledge of Y-parameters and their conversion to S-parameters.
  • Basic circuit analysis involving inductors and transmission lines.
NEXT STEPS
  • Study the derivation and implications of S-parameters in microwave engineering.
  • Learn about Y-parameter to S-parameter conversion techniques.
  • Explore the significance of negative S-parameters and their physical interpretations.
  • Investigate the role of phase shifts in transmission lines and their effects on signal integrity.
USEFUL FOR

Electrical engineers, microwave engineers, and students studying network theory who are interested in understanding S-parameters and their applications in circuit design and analysis.

Xyius
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EDIT: Oops! I posted this in the wrong section! Meant to post in engineering section!

I am not sure if I am doing this problem correctly or not. It is very simple.

1. Homework Statement

A 2 port network consists of just a series inductor with ##Z=j 100 \Omega## in a ##50 \Omega## system. Determine the corresponding S-parameters.

Homework Equations


S Parameter matrix equations
b_1 = S_{11}a_1 + S_{12}a_2
b_2 = S_{21}a_1 + S_{22}a_2
Where
a_1=\frac{V_1+Z_0I_1}{2\sqrt{Z_0}},
a_2=\frac{V_2+Z_0I_2}{2\sqrt{Z_0}},
b_1=\frac{V_1-Z_0I_1}{2\sqrt{Z_0}},
b_2=\frac{V_2-Z_0I_2}{2\sqrt{Z_0}}.

The Attempt at a Solution



First I let ##a_1=0## by terminating the line with an impedance equal to the characteristic impedance so ##V_1=-Z_0I_1##. Doing this allows me to use my first two equations above and solve for both ##S_{22}## and ##S_{12}##.

S_{22}=\frac{b_2}{a_2}=\frac{V_2-Z_0I_2}{V_2+Z_0I_2}=\frac{Z_{out}-Z_0}{Z_{out}+Z_0}

When the circuit is terminated on the LHS with a resistor equal to the characteristic impedance, the output impedance is simply ##Z+Z_0##. Plugging everything in, this gives me.
S_{22}=\frac{1}{2}(1+j)

This part wasn't a problem, getting ##S_{12}## is giving me confusion. The equation is, (we will use ##I_1=I_2##)
S_{12}=\frac{b_1}{a_2}=\frac{V_1-Z_0I_1}{V_2+Z_0I_2}=\frac{\frac{V_1}{I_2}-Z_0}{\frac{V_2}{I_2}+Z_0}.

Because ##a_1=0## we know that ##V_1=-Z_0I_1=-Z_0I_2##, also ##V_2/I_2=Z_0##thus,
S_{12}=\frac{-2Z_0}{\frac{V_2}{I_2}+Z_0}=\frac{-2Z_0}{2Z_0}=-1.

This is what I am confused about. Can the transmission coefficient be negative? Would that just mean that the transmitted energy simply has a ##\pi## phase shift? Am I doing this right?

The other two parameters can be obtained by similar means.
 
Since the inductor is imbedded in a Z0 = 50 ohm system you can
1. find the y parameters for the 2-port.
2. normalize to the 50 ohm environment (source and load = 50 ohms, possible xmsn line Z0 also = 50 ohms connecting the source to the input port and the output port to the load)
3. convert to s parameters using conversion tables.

This is probably not the approach used by seasoned microwave engineers but I like it because I understand y parameters better than s parameters.
 

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